3 years ago

Help math problem word problem

Mathematics

1 answer:

lina2011 [118]3 years ago

3 0

6.1% of 36,000 = 2196
36,000-2196=33,804

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I need help please. 2nd box: meters, cubic meters, or square meters.

Fudgin [204]

Answer:

I believe it is meters

Step-by-step explanation:

I think so because the rectangle is labeled with meters

6 0

3 years ago

Read 2 more answers

Which of the following is the standard equation of the ellipse with vertices at (1,0) and (27,0) and an eccentricity of 5/13?

Dovator [93]

The equation of the elipse is given by:

$\frac{(x - 14)^2}{169} + \frac{y^2}{144} = 1$

The equation of an elipse of center $(x_0, y_0)$ is given by:

$\frac{(x - x_0)^2}{a^2} + \frac{(y - y_0)^2}{b^2} = 0$

Values a and b are found according to the <u>vertices and the eccentricity</u>.

It has vertices at (1,0) and (27,0), thus:

$x_0 = \frac{27 + 1}{2} = 14$

$y_0 = \frac{0 + 0}{2} = 0$

$a = \frac{27 - 1}{2} = 13$

$a^2 = 169$

It has eccentricity of $\frac{5}{13}$ , thus:

$\frac{5}{13} = \frac{c}{a}$

$\frac{5}{13} = \frac{c}{13}$

$c = 13$

Thus, b is given according to the following equation:

$c^2 = a^2 - b^2$

$b^2 = a^2 - c^2$

$b^2 = 169 - 25$

$b = \sqrt{144}$

$b = 12$

The equation of the elipse is:

$\frac{(x - 14)^2}{169} + \frac{y^2}{144} = 1$

A similar problem is given at brainly.com/question/21405803

3 0

3 years ago

Please help me with this

madreJ [45]

Answer:

the answer is the first one hope this helps

Step-by-step explanation:

3 0

3 years ago

Domain and range of y=-.50x+12

Alja [10]

Domain: all real numbers
Range: y<0

3 0

3 years ago

PLEASE HELP MATH EXPAND LOG

blsea [12.9K]

Answer:

½log3 + ½logx

Step-by-step explanation:

½(log(3x))

½(log3 + logx)

½logx + ½log3

8 0

3 years ago