Answer:
answer is : Cos(13pi/8) = 0.3826
Step-by-step explanation:
We have, Cos (13pi/8)
Since 13pi/8 can be shown as 3pi/2 < 13pi/8 < 2pi
Hence 13pi/8 lies on fourth quadrant.
In fourth quadrant cosine will be positive.
Cos (13pi/8) = cos(3pi/2 + pi/8)
applying formula cos(A+B) = cos A cosB - sinAsinB
i.e Cos(3pi/2 + pi/8) = cos(3pi/2)cos(pi/8) - sin(3pi/2)sin(pi/8)
∵ Remember cos(3pi/2) =0 , sin(3pi/2) = -1
Cos(3pi/2 + pi/8) = 0 cos(pi/8) - (-1)sin(pi/8)
Cos(3pi/2 + pi/8) = 0 + 0.3826
Cos(3pi/2 + pi/8) = 0.3826
Hence we got Cos(13pi/8) = 0.3826
Answer: The area of triangle ΔXYZ is 12 square inches.
Step-by-step explanation:
Since we have given that
RS = 3 inches
XY = 2 inches
Area of ΔRST = 27 in²
Since ΔRST is similar to ΔXYZ.
So, using the "Area similarity theorem":
![\dfrac{\Delta RST}{\Delta XYZ}=\dfrac{RS^2}{XY^2}\\\\\dfrac{27}{\Delta XYZ}=\dfrac{3^2}{2^2}\\\\\dfrac{27}{\Delta XYZ}=\dfrac{9}{4}\\\\\Delta XYZ=3\times 4=12\ in^2](https://tex.z-dn.net/?f=%5Cdfrac%7B%5CDelta%20RST%7D%7B%5CDelta%20XYZ%7D%3D%5Cdfrac%7BRS%5E2%7D%7BXY%5E2%7D%5C%5C%5C%5C%5Cdfrac%7B27%7D%7B%5CDelta%20XYZ%7D%3D%5Cdfrac%7B3%5E2%7D%7B2%5E2%7D%5C%5C%5C%5C%5Cdfrac%7B27%7D%7B%5CDelta%20XYZ%7D%3D%5Cdfrac%7B9%7D%7B4%7D%5C%5C%5C%5C%5CDelta%20XYZ%3D3%5Ctimes%204%3D12%5C%20in%5E2)
Hence, the area of triangle ΔXYZ is 12 square inches.
if you do 14-4 which is equal to 10