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Natalka [10]
2 years ago
10

How much would 5 chicken and noodle meals and 1 order of chicken and potatoes be if the tax on 1 meal is $0.18. Chicken noodle c

osts $7.35 and chicken and potatoes costs $6.25.
Mathematics
1 answer:
Nostrana [21]2 years ago
7 0

Answer:$44.08

Step-by-step explanation:

$7.35 x 5 = $36.75

$0.18 x 5 = $0.90

$0.90 + $36.75 = $37.65

$37.65 + $6.25 + $0.18 = $44.08

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The Fruitz fruit and vegetable shop is selling grapes at a price which is 10% cheaper than the Happy Fruiterer fruit and vegetab
sdas [7]

Answer:

(a) It costs $55 at Happy Fruiterer

(b) It will cost $49.64

(c) It is cheaper at Happy Fruiterer the second week

Step-by-step explanation:

Since Fruitz shop sells as 10% less than Happy Fruiterer at $50

10% more of $50 = 50 × 10/100 + 50

= $5 + $50 = $55

(a) n Kg of grapes will cost $55 at Happy Fruiterer

(b) if Happy Fruits discounts $55 by 5%, we will have

55 × 5/100 = 2.75

that is $55 - $2.75 = $52.25

If it is discounted further at 5% more the following week, we will have

$52.25 × 5/100 = $2.6125

≈ $2.61

Then the new price for the 2nd week is $52.25 - $2.61

= $49.64

(c) at the second wee of discounting, Fruitz shop still sells at $50 will Happy Fruiterer now see at $49.64. Therefore, it is cheaper at Happy Fruiterer

8 0
2 years ago
The population of bacteria in a petri dish doubles every 24 h. The population of the bacteria is initially 500 organisms. How lo
liberstina [14]

Answer:

16.34 hours

Step-by-step explanation:

According to the given information we can see that the case is of exponential growth

Hence, we will use the formula

A=P(2)^\frac{t}{24}

Here A =800 is the amount that is needed to reach

P is the initial amount that is 500

We have to find the time it will take to reach 800 that is we need to find t

On substituting the values in the formula we get

800=500(2)^\frac{t}{24}

On simplification we get

\Rightarrow\frac{8}{5}=(2)^\frac{t}{24}

Taking log on both sides we get

\Rightarrow\log\frac{8}{5}=\log(2)^\frac{t}{24}

using \log\frac{m}{n}=\log m-\log n

And \log a^m=m\log a

\Rightarrow\log{8}-\log{5}=\frac{t}{24}\log2

Now substituting values of log 8=0.903, log 5=0.698 and log 2=0.301 we get

\Rightarrow 0.903-0.698=\frac{t}{24}0.301

\Rightarrow 0.205=\frac{t}{24}0.301

\Rightarrow \frac{0.205}{0.301}\cdot 24=t

\Rightarrow t=16.34

8 0
3 years ago
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