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nikklg [1K]
3 years ago
5

Choose the symbol that correctly compares these mixed numbers.

Mathematics
2 answers:
Anastasy [175]3 years ago
5 0

Answer:

It is 7 2/11 is less then 7 4/10

Step-by-step explanation:

You do not have to worry about the whole number because they are the same. You have to compare the fractions, so if comparing fractions 10 is less then 11 so 1/10 has a larger space then 1/11. That is how i got the answer. Hope this helps. Am I right?

ira [324]3 years ago
3 0

Answer:

\huge\purple{\overline{\quad\quad\quad\quad\quad\quad\quad\quad\quad \ \ \ }}

7  \frac{2}{11}  < 7  \frac{4}{10}

Answer: B

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Answer:

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Step-by-step explanation:

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3 years ago
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Need Help on this Part
Gnoma [55]

To determine the 'intervals of increase' and 'intervals of decrease' we can refer to the graph with respect to the x - axis.

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• Respectively our 'intervals of decrease' as inequalities would be - ∞ < x < 1, and 3 < x < 4. Our intervals of decrease would then be (- ∞, 1) and (3,4).

• We are left with our local extrema and absolute extrema. Now remember the absolute extrema is the absolute lowest point in the whole graph, while the local extrema is the lowest point in a restricted interval. In this case our local extrema is our maximum, (3,1). But this maximum is not greater than the starting point (0, 4) so it appears, and hence their is no absolute extrema.

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3 years ago
Solve by using the quadratic formula:<br> x2 - 6x + 7 = 0
IgorC [24]

Final Answer: x = 3 + \sqrt{2}, 3 - \sqrt{2}

Steps/Reasons/Explanation:

Question: Solve by using the quadratic formula:  x^{2}  - 6x + 7 = 0.

<u>Step 1</u>: Use the Quadratic Formula.

x = \frac{6 + \sqrt[2]{2} }{2}, \frac{6 - \sqrt[2]{2} }{2}

<u>Step 2</u>: Simplify solutions.

x = 3 + \sqrt{2}, 3 - \sqrt{2}

~I hope I helped you :)~ The quadratic formulaic is attached in an image.

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