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Tems11 [23]
3 years ago
13

Heather finally narrowed her clothing choices for the big party down to three skirts, two tops and four pies of shoes. How many

different outfits are possible from these choices?
Mathematics
1 answer:
Zigmanuir [339]3 years ago
6 0
<h3>Answer: 24</h3>

To get this answer, we multiply the values given to us

3*2*4 = 6*4 = 24

So that's why there are 24 different outfits possible.

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The amount of profit, p, you earn by selling knives, k, can be determined by: p=200k-500 a) Determine the constraints on profit
Natalka [10]
We are given with the formula
p = 200k - 500
a) The constraint for this formula is obtained from the idea that the profit must be positive
200k - 500 > 0 
k > 500/200
k > 2.5
b) To make 14000 profit
 14000 = 200k - 500
k = 72.5 or 73 knives must be sold
3 0
3 years ago
A jar contains 45 red candies and 60 black candies. Suppose a candy is selected at random. What are the odds against selecting a
uysha [10]

Answer:

3:4.

Step-by-step explanation:

To work this out we need to find the highest multiple of 45 and 60.

15 is the largest number that goes into both of them so what we are going to do now is divide both number by 15.

45 divided by 15 = 3

60 divided by 15 = 4

Therefore the odds of selecting a red candy is 3:4.

Hope that helps. x

7 0
3 years ago
Exponential growth/decay problem 1
RUDIKE [14]

Answer:

a) growth

b) $500

c) 6% = 0.06

d) f(x)=500(1.06)^x

e) $595.51

Step-by-step explanation:

<u />

<u>Part (a)</u>

Exponential GROWTH, since interest is applied to the account each year.

<u>Part (b)</u>

Initial amount = $500

<u>Part (c)</u>

Growth factor = 6% = 0.06 (in decimal form)

<u>Part (d)</u>

General form of exponential growth function:

f(x)=a(1+r)^x

where:

  • a = initial amount
  • r = rate of growth (in decimal form)
  • x = time (in years)

Given:

  • a = 500
  • r = 0.06

\implies f(x)=500(1+0.06)^x

\implies f(x)=500(1.06)^x

<u>Part (e)</u>

when x = 3

\begin{aligned}\implies f(3) & =500(1.06)^3\\ & = 595.51\: \sf(nearest\:hundredth)\end{aligned}

5 0
2 years ago
Calculator
satela [25.4K]
3 should be it......
4 0
3 years ago
Find the solution of this system of two linear equations using substitution 11x+3y=103 and y =3x+1
Lesechka [4]
11x+3y=103 and y=3x+1. 

11x+3(3x+1)=103  -----> plug in (3x+1) for y in the first equation.  You will want to distribute the 3 to the 3x+1 to get something that looks like:

11x+9x+3=103    ------> now you want to combine like terms 

20x+3=103 ---> subtract 3 from both sides
20x=100   ----> divide both sides by 20
x=5    

y=3(5)+1     ---> I like to plug in this to the equation that already has y isolated.  3*5 is 15, add 1 and you find that y=16.

(5, 16) will be your final answer (:
8 0
3 years ago
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