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Tems11 [23]
3 years ago
13

Heather finally narrowed her clothing choices for the big party down to three skirts, two tops and four pies of shoes. How many

different outfits are possible from these choices?
Mathematics
1 answer:
Zigmanuir [339]3 years ago
6 0
<h3>Answer: 24</h3>

To get this answer, we multiply the values given to us

3*2*4 = 6*4 = 24

So that's why there are 24 different outfits possible.

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I need help on this
Tanya [424]

Answer:

x = 20

Step-by-step explanation:

Please see the step-by-step solution in the picture attached below.

I hope this answer will help you. Have a nice day !

4 0
3 years ago
I need help asap!!!!! pls you’ll earn brainlist
Anni [7]

Answer:

1 % decrease

Step-by-step explanation:

The percent of decrease time can be written as the expression \frac{200}{200}-\frac{198}{200} = \frac{2}{200}. Now, we convert the fraction into a decimal: \frac{2}{200} = \frac{1}{100} = 0.01. We can convert this decimal into a percentage: 0.01*100 = 1%.

<u><em>PLZ MARK BRAINLIEST!!!</em></u>

6 0
3 years ago
A spinner has 8 equally sized sections, 4 of which are gray and 4 of which are blue. The spinner is spun twice. What is the prob
SVEN [57.7K]

Answer: 1/2

Step-by-step explanation: 4/8 =1/2

6 0
3 years ago
Cheryl plans to bake cookies tomorrow and needs to purchase chocolate chips and pecans for no more than $25 total. Chocolate chi
boyakko [2]

The inequality that correctly represents this scenario is given as follows:

2x + 5y \leq 25

The graph is given at the end of the question.

<h3>What is a system of inequalities?</h3>

A system of inequalities is when two or more variables are related, and inequalities are built to find the values of each variable.

In this problem, the variables are given as follows:

  • Variable x: number of chocolate chips purchased.
  • Variable y: number of pecans sold.

Chocolate chips are $2 per pound and pecans are $5 per pound. She wants to spend at most $25, hence:

2x + 5y \leq 25

More can be learned about a system of inequalities at brainly.com/question/3656398

#SPJ1

6 0
2 years ago
Are E1 and E2 mutually exclusive events? Why or why not?
Kobotan [32]

Answer:

E1 and E2 are not mutually exclusive events. They have outcomes in common because a winning number can be both red and odd.

Step-by-step explanation:

EDMENTUM

4 0
3 years ago
Read 2 more answers
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