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kolbaska11 [484]
3 years ago
10

Please help its due today

Mathematics
1 answer:
luda_lava [24]3 years ago
6 0
The answer is x and y have a weak, positive correlation.
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X=7w^+4w-6 and y=w^-11w+13
aleksandr82 [10.1K]
Although the terms might seem intimidating, this is a simple substitution problem.

X + Y = _______
Substitute the values of X and Y in terms of w
(7w^2 + 4w - 6) + (w^2 - 11w + 13) = ______
Now all you need to do is combine like terms (terms that have the same variables raised to the same power)
8w^2 - 7w + 7

Final Answer: 8w^2 - 7w + 7
3 0
3 years ago
What is the answer to “x” in <br> y = 84x + 625
solong [7]

could u give me more detail?

(like y’s number)

4 0
3 years ago
Read 2 more answers
PLEASEPLEASE HELPPPP!!! This is quadratics, and I need help and please show the steps. I’m not sure how to approach this, but I
Len [333]
Start with the bottom equation and rearrange it so that it's a "y =" equation like so:
0 = 2x + 1 - y ->
y = 2x + 1

now since you know "y" you may substitute that equation 2x + 1 into "y" of the first given equation to be:
x^2 = (2x + 1) - 7 + 5x
then simplify
x^2 = 7x - 6 (I just put together like terms here to simplify the equation)

then you can make it to be: x^2 - 7x + 6 = 0
and there's your new and nice equation. now just solve for "x" using the quadratic formula or any other formula that you know

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6 0
3 years ago
Determine the sample space of all of the possible outcomes of choosing a card numbered 1, 2, 3, or 4 and a blue, green, or yello
Alex17521 [72]

Answer:

Answer 2

Step-by-step explanation:

8 0
3 years ago
68 1/4% as a decimal
eduard

Answer:   The correct answer is:  " 0.6825 ".

_______________________________________________

Step-by-step explanation:

_______________________________________________

We are asked to convert:  " 68 \frac{1}{4} % " ;  to a "decimal" .

_______________________________________________

1)  Rewrite:  " 68 \frac{1}{4} " ;   as a "decimal value" :

           " 68 \frac{1}{4} "  =   68 + \frac{1}{4} ;

         →  " \frac{1}{4} "  =  1 / 4  =  1 ÷ 4 =  0.25  . (use calculator).

Or:     →    " \frac{1}{4} "  =  " \frac{?}{100} " ;

   

→  Find the "?" value:

_______________________________________________

Let us consider the "denominators" ;

          →    4 * (what value)  =  100 :  

            →  100/ 4 = 100 ÷ 4 = 25 .

So:   4 * 25  = 100;  

So, to find the "?" value in the numerator:

→   1 * 25 = ("?") ;  

→   1 * 25 = 25 ;

_______________________________________________

So, we have:

_______________________________________________

→    " \frac{1}{4} "  =  " \frac{?}{100} " ;

Rewrite; and replace the "?" value with our know value:  " 25 " :

→    " \frac{1}{4} "  =  " \frac{25}{100} " ;

Note that:  " \frac{25}{100} "  ;

                        =  25/100 = 25 ÷ 100  = 0.25  .  {Use calculator.}.,

               Or:  25 ÷ 100 = ?   ;  

→  When dividing by "100" ;  we take the number; and move the decimal point  back 2 (two) spaces;  since "100" has 2 (two) zeros.

                             →   25 ÷ 100  =  25.  ÷  100  =  .25;  

                                   →  write as:  " 0.25" .

_______________________________________________

So:  " 68  \frac{1}{4} "  =   68  +  0.25 =   68.25  .

As such:  " 68  \frac{1}{4} % "  =  68.25 % ;

_______________________________________________

Now, we write:  " 68.25 % " as a decimal ;

<u>Note</u>:  " % " ; or "percent" ;  means "per hundred" ; or "parts per hundred" ;

or;  "divide by 100" ;

_______________________________________________

 So;  to write:  " 68.25 % " as a decimal ;

                         →   " 68.25 ÷ 100 "  =  0.6825 .  {← Use calculator.}.

                 Or:   → 68.2 ÷ 100 = ?   ;  

→  When dividing by "100" ;  we take the number; and move the decimal point  back 2 (two) spaces;  since "100" has 2 (two) zeros.

                             →   " 68.25 ÷ 100 "  ÷  100  =  .6825 ;  

                                   →  write as:  " 0.6825 " .

_______________________________________________

The answer is:  " 0.6825 " .

_______________________________________________

Hope this answer is helpful to you!

          Wishing you the best in your academic pursuits

                — and within the "Brainly" community!

_______________________________________________

6 0
3 years ago
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