Answer:
$6,900
Step-by-step explanation:
Let
x = Amount Monica should earn each month
Rent per month = $2,300
Monica knows that she should spend no more than 1/3 of her income on her rent
1/3 of her Income = rent
1/3 of x = 2,300
1/3x = 2,300
x = 2,300 ÷ 1/3
x = 2,300 * 3/1
x = $6,900
Monica should earn $6,900 each month to afford the rent on her cool new place
Answer:
20, c
Step-by-step explanation:
50-30=20 Go 50 down a number line from 50, you're at 0, then go back up 30. Where are you at? 20 Hope this helps! Have a good day! :)
The expression will be x-3.
Answer:
66170 mm
Step-by-step explanation:
0.06617 km * 1000 km/m * 1000 m/mm = 66170 mm
The valid conclusions for the manager based on the considered test is given by: Option
<h3>When do we perform one sample z-test?</h3>
One sample z-test is performed if the sample size is large enough (n > 30) and we want to know if the sample comes from the specific population.
For this case, we're specified that:
- Population mean =
= $150 - Population standard deviation =
= $30.20 - Sample mean =
= $160 - Sample size = n = 40 > 30
- Level of significance =
= 2.5% = 0.025 - We want to determine if the average customer spends more in his store than the national average.
Forming hypotheses:
- Null Hypothesis: Nullifies what we're trying to determine. Assumes that the average customer doesn't spend more in the store than the national average. Symbolically, we get:

- Alternate hypothesis: Assumes that customer spends more in his store than the national average. Symbolically

where
is the hypothesized population mean of the money his customer spends in his store.
The z-test statistic we get is:

The test is single tailed, (right tailed).
The critical value of z at level of significance 0.025 is 1.96
Since we've got 2.904 > 1.96, so we reject the null hypothesis.
(as for right tailed test, we reject null hypothesis if the test statistic is > critical value).
Thus, we accept the alternate hypothesis that customer spends more in his store than the national average.
Learn more about one-sample z-test here:
brainly.com/question/21477856