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amid [387]
3 years ago
12

A person in a rowboat two miles from the nearest point on a straight shoreline wishes to reach a house six miles farther down th

e shore. if the person can row at a rate of 3 mi/h and walk at a rate of 5 mi/h, find the least amount of time required to reach the house. how far from the house should the person land the rowboat?

Mathematics
1 answer:
DanielleElmas [232]3 years ago
6 0
To solve this problem, we know that time it takes the person to travel at distance is given by t = distance / rate .So in the attached file, you can see the step by step solution for this problem.
And the answer for this question is: The person should walk 6 - 1.5 miles or 4.5 miles along the shore

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Question is on the picture !
Nataly [62]

Answer: 122.5

======================================================

Explanation:

First thing to do is to find the perimeter of figure B. Add up all the sides and we get: 5+9+9+12 = 14+21 = 35.

The scale factor 7:2 means that if the perimeter of figure A was 7, then the perimeter of figure B would be 2. Or it could be 14 for A and 4 for B. And so on. The idea is that the two perimeters scale up or down together. This allows us to set up the proportion below in which we can solve for x

(perimeter of A)/(perimeter of B) = 7/2

x/35 = 7/2

x*2 = 35*7 .... cross multiply

2x = 245

2x/2 = 245/2 .... divide both sides by 2

x = 122.5

The perimeter of figure A is 122.5

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Step-by-step explanation:

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