Answer:
c. (-2, 5)
Step-by-step explanation:
y - 2 = 3/2(x + 4)
to know which is the correct option we have to replace the equation x and y with what is in the point
a.
y - 2 = 3/2(x + 4)
(-1) - 2 = 3/2((-2) + 4)
-3 = 3/2(2)
-3 = 3
Wrong
b.
y - 2 = 3/2(x + 4)
(5) - 2 = 3/2((-6) + 4)
3 = 3/2(-2)
3 = -3
Wrong
c.
y - 2 = 3/2(x + 4)
(5) - 2 = 3/2((-2) + 4)
3 = 3/2(2)
3 = 3
Correct
d.
y - 2 = 3/2(x + 4)
(-1) - 2 = 3/2((6) + 4)
-3 = 3/2(10)
-3 = 15
Wrong
1. expand using place value.
337,060 = 300,000 + 30,000 + 7,000 + 000 + 60 + 0
Next, we will use exponents:
300,000 = 3 * 10^5
30,000 = 3 * 10^4
7,000 = 7 * 10^3
000 = 0 * 10^2
60 = 6 * 10
0 = 0 * 10^0
then after combing these exponents, we can write the number as:
337,060 = 3 * 10^5 + 3 * 10^4 + 7 * 10^3 + 0 * 10^2 + 6 * 10 + 0 * 10^0
Finally, removing the meaningless zeroes, we would end up with:
337,060 = 3 * 10^5 + 3 * 10^4 + 7 * 10^3 + 6 * 10
Answer:
lets just say the f stands for 1 and 1 times negative 4 is negative 4
and 5 will stay 5 the equation would be -4/5 so after u divide the 4 and the five you get negative 1
This problem is a combination of the Poisson distribution and binomial distribution.
First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961
For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5) or approximately
=0.00006181
