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2 years ago

How to write 3,028,002 In Word Form

Mathematics

2 answers:

allsm [11]2 years ago

5 0

<span>three million twenty eight thousand two=3,028,002
</span>

Scorpion4ik [409]2 years ago

3 0

Three million twenty-eight thousand and two

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nick is given 450 to sepend on a vacatio. he decides to spend $5 a day the amount nick has left and the number of days are relat

omeli [17]

Answer:

m= 450 - (5*n)

Step-by-step explanation:

m is the money left

n is the days

7 0

2 years ago

Find the solution for the system of linear equations by elimination: 2x+y=9,3x-y=16

alexandr402 [8]

Answer:

(-5,-1)

Step-by-step explanation:

2x+y=9 -> y=-2x+9

3x-y=16

3x-(-2x+9)=16

3x+2x-9=16

5x-9=16

5x-9 (+9)=16 (+9)

5x=25

x=5

no plug in 5 to x in any equation above

2(5)+y=9

10+y (-10)=9 (-10)

y=-1

so the answer is (-5,-1)

hope it's correct! and hope i helped

3 0

2 years ago

Read 2 more answers

One measure of an athlete’s ability is the height of his or her vertical leap. Many professional basketball players are known fo

almond37 [142]

Answer:

(1) P( $\bar X$ < 26 inches) = 0.0436

(2) P(27.5 inches < $\bar X$ < 28.5 inches) = 0.2812

Step-by-step explanation:

We are given that the mean vertical leap of all NBA players is 28 inches. Suppose the standard deviation is 7 inches and 36 NBA players are selected at random.

Firstly, Let $\bar X$ = mean vertical leap for the 36 players

Assuming the data follows normal distribution; so the z score probability distribution for sample mean is given by;

Z = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean vertical leap = 28 inches

$\sigma$ = standard deviation = 7 inches

n = sample of NBA player = 36

(1) Probability that the mean vertical leap for the 36 players will be less than 26 inches is given by = P( $\bar X$ < 26 inches)

P( $\bar X$ < 26) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{26-28}{\frac{7}{\sqrt{36} } }$ ) = P(Z < -1.71) = 1 - P(Z $\leq$ 1.71)

= 1 - 0.95637 = 0.0436

(2) <em>Now, here sample of NBA players is 26 so n = 26.</em>

Probability that the mean vertical leap for the 26 players will be between 27.5 and 28.5 inches is given by = P(27.5 inches < $\bar X$ < 28.5 inches) = P( $\bar X$ < 28.5 inches) - P( $\bar X$ $\leq$ 27.5 inches)

P( $\bar X$ < 28.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{28.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z < 0.36) = 0.64058 {using z table}

P( $\bar X$ $\leq$ 27.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{27.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z $\leq$ -0.36) = 1 - P(Z < 0.36)