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OLga [1]
3 years ago
14

Which of the following lists all of the positive factors of 18?

Mathematics
1 answer:
babymother [125]3 years ago
4 0

The square root of 18 is 4.2426, rounded down to the closest whole number is 4. Testing the integer values 1 through 4 for division into 18 with a 0 remainder we get these factor pairs: (1 and 18), (2 and 9), (3 and 6). The factors of 18 are 1, 2, 3, 6, 9, 18.

Step-by-step explanation:

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C = 4+0. 10t what is the charge to rent a paddle boat for 20 minutes?
Blababa [14]
The charge should be $6. I believe I set this up correctly; let me know if there are any errors. Hope this is helpful & accurate.

5 0
2 years ago
At a bake sale, as student spent $11.00 buying 3 brownies and 5 cookies. His friend spent $3.95 buying 1 brownie and 2 cookies.
riadik2000 [5.3K]

Answer:

$$2.25

Step-by-step explanation:

Let b = the cost of one brownie, c = cost of one cookie

3b + 5c = 11

b+2c = 3.95

Times 3 on both sides on the second equation above to get the following:

3b + 6c = 11.85

3b+6c - (3b+5c) = 11.85-11

3b+6c-3b-5c = 0.85

c = 0.85

To find the value of b, use substitution:

b+2c = 3.95

b = 3.95-2c

= 3.95 - 2\times0.85

= 2.25

\therefore the cost of a brownie is $$2.25

Hope this helps :)

4 0
3 years ago
Which of the following is equal to the rational expression when x -2 or -1? x^2-4/(x+2)(x+1)
Orlov [11]

Answer:

(x+2)(x+1)

Step-by-step explanation:

Assuming im interpreting this correctly, it should be (x+2)(x+1), since if you plug in -2 and -1, it will give you 0, which is the answer.

8 0
3 years ago
A loan of $900 will be repaid in 36 installment of $30.22 each .what is the finance charge for the loan
Marat540 [252]

i hope this is what you are looking for but 36 times 30.22 equals 1087.92 subtract from 900 which is $187.92

<h2>$187.92 for finance charge for loan</h2>
8 0
3 years ago
If a coin is tossed three times, find probability of getting
Assoli18 [71]

{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}

‣ A coin is tossed three times.

{\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}

‣ The probability of getting,

1) Exactly 3 tails

2) At most 2 heads

3) At least 2 tails

4) Exactly 2 heads

5) Exactly 3 heads

{\large{\textsf{\textbf{\underline{\underline{Using \: Formula :}}}}}}

\star \: \tt  P(E)= {\underline{\boxed{\sf{\red{  \dfrac{ Favourable \:  outcomes }{Total \:  outcomes}  }}}}}

{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}

★ When three coins are tossed,

then the sample space = {HHH, HHT, THH, TTH, HTH, HTT, THT, TTT}

[here H denotes head and T denotes tail]

⇒Total number of outcomes \tt [ \: n(s) \: ] = 8

<u>1) Exactly 3 tails </u>

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

\therefore  \sf Probability_{(exactly  \: 3 \:  tails)}  =  \red{ \dfrac{1}{8}}

<u>2) At most 2 heads</u>

[It means there can be two or one or no heads]

Here

• Favourable outcomes = {HHT, THH, HTH, TTH, HTT, THT, TTT} = 7

• Total outcomes = 8

\therefore  \sf Probability_{(at \: most  \: 2 \:  heads)}  =  \green{ \dfrac{7}{8}}

<u>3) At least 2 tails </u>

[It means there can be two or more tails]

Here

• Favourable outcomes = {TTH, TTT, HTT, THT} = 4

• Total outcomes = 8

\longrightarrow   \sf Probability_{(at \: least \: 2 \:  tails)}  =  \dfrac{4}{8}

\therefore  \sf Probability_{(at \: least \: 2 \:  tails)}  =   \orange{\dfrac{1}{2}}

<u>4) Exactly 2 heads </u>

Here

• Favourable outcomes = {HTH, THH, HHT } = 3

• Total outcomes = 8

\therefore  \sf Probability_{(exactly \: 2 \:  heads)}  =  \pink{ \dfrac{3}{8}}

<u>5) Exactly 3 heads</u>

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

\therefore  \sf Probability_{(exactly \: 3 \:  heads)}  =  \purple{ \dfrac{1}{8}}

\rule{280pt}{2pt}

8 0
2 years ago
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