Answer:
The wedge cut from the first octant ⟹ z ≥ 0 and y ≥ 0 ⟹ 12−3y^2 ≥ 0 ⟹ 0 ≤ y ≤ 2
0 ≤ y ≤ 2 and x = 2-y ⟹ 0 ≤ x ≤ 2
V = ∫∫∫ dzdydx
dz has changed from zero to 12−3y^2
dy has changed from zero to 2-x
dx has changed from zero to 2
V = ∫∫∫ dzdydx = ∫∫ (12−3y^2) dydx = ∫ 12(2-x)-(2-x)^3 dx =
24(2)-6(2)^2+(2-2)^4/4 -(2-0)^4/4 = 20
Step-by-step explanation:
Answer:
what are the answers?
Step-by-step explanation:
A vertical asymptotic is a point at which y approaches positive or negative infinite, or both, and y is undefined at that x value.
Of the options, the reciprocal has a vertical asymptote. When approaches zero, y approaches 1÷0, or infinite.
The logarithmic function also has a vertical asymptote at x=0. Let's use f(x) =log base 10 (x) as an example. This function describes the exponent you'd have to put on 10 to get x. When x=0, we have a bit of a problem. What power can you raise 10 to to get 0? The answer is negative infinite, which would be
1/ (10^∞) = 0.
In the first problem you are given a formula (y = 3x), along with a table.
From the data in the table, find the slope of the linear equation that relates x and y in that data.
Then compare the two slopes. Which is the greater? the smaller?
