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3 years ago

Sometimes I am a sphere, sometimes i am a banana, and sometimes i am not there at all. What am I

Mathematics

2 answers:

gayaneshka [121]3 years ago

7 0

Answer:

Your a moon

Step-by-step explanation:

you described phases of the moon

SVEN [57.7K]3 years ago

4 0

First off, capitalize that "I" please.Secondly, you are a moon.

Reason:A full moon is a sphere, a crescent moon looks like a banana, and sometimes you can't see the moon at all.

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QUESTION 05 (10 points) - Sample Size Determination in Estimating Population Mean In this hypothetical scenario, you are working

GREYUIT [131]

Answer:

$ 37.32 is the required budget in dollars (2 decimals) to have the cheese burgers in your sample

Step-by-step explanation:

Here

Z∝ =1.64

Standard Deviation=S= 0.21

Sampling Error= SE= 0.05

As Sampling Error is found by

SE= z * s/√n

√n= z*s/ SE

n= (z* s/ SE)²

We use the above formula to calculate N

N= ( Z * S/SE)²

N= (1.64 * 0.21/0.05)²

N= 28.9296= 28.93

Cost of N number of burgers

= Cost *N

= $1.29 * 28.93= $ 37.32 is the required budget in dollars (2 decimals) to have the cheese burgers in your sample

8 0

4 years ago

Judith is digging for sandstone at a geological site. She has 160 meters of rope and 4 stakes to mark off a rectangular area. Wh

astra-53 [7]

Hello,

Answer D

2*70+2*10=140+20=160 (m)

4 0

3 years ago

Suppose that the probabilities of a customer purchasing 0, 1, or 2 books at a book store are 0.20.2, 0.30.3, and 0.50.5, res

PIT_PIT [208]

Answer:

0.78

Step-by-step explanation:

We have the next probability distribution:

X P(X)

0 0.2

1 0.3

2 0.5

As we can see when we add all the probabilites the result is 1. Now calculating the mean we have:

$mean=\mu=(0\times0.2)+(1\times 0.3)+(2\times 0.5)=0+0.3+1=1.3$

The standard deviation is:

$\sigma=\sqrt{\sum(x-\mu)^{2}(P(x))}$

Then using the data that we have:

$\sigma=\sqrt{\sum(x-\mu)^{2}(P(x))}\\\sigma=\sqrt{(0-1.3)^{2}(0.2)+(1-1.3)^{2}(0.3)+(2-1.3)^{2}(0.5)}\\\\\sigma=\sqrt{(-1.3)^{2}(0.2)+(-0.3)^{2}(0.3)+(0.7)^{2}(0.5)}\\\\\sigma=\sqrt{(1.69)(0.2)+(0.09)(0.3)+(0.49)(0.5)}\\\\\sigma=\sqrt{0.338+0.027+0.245}\\\\\sigma=\sqrt{0.61}\\\\\sigma=0.78\\$

Then the standard deviation is 0.78

6 0

3 years ago

The set of numbers 1, 7, 11, and 36 contains values of m. What value of m makes the equation below true? 4m + 8 = 36

german

Answer:

i think its 7

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Let f(x) = (x − 3)−2. find all values of c in (1, 4) such that f(4) − f(1) = f '(c)(4 − 1). (enter your answers as a comma-separ

Verizon [17]

If the function is $(x-3)^{-2}$ and f(4) − f(1) = f '(c)(4 − 1) then there is not any answer.

Given function is $(x-3)^{-2}$ and f(4) − f(1) = f '(c)(4 − 1).

In this question we have to apply the mean value theorem, which says that given a secant line between points A and B, there is at least a point C that belongs to the curve and the derivative of that curve exists.

We begin by calculating f(2) and f(5):

f(2)= $(2-3)^{-2}$