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const2013 [10]
2 years ago
7

Explain and discuss why engineers usually want the minimum variance unbiased estimator achieved by using the MVUE in making engi

neering decisions, and impacts might be seen if another estimator is chosen at times? Try to use (MVUE). What benefits are what risks or hypothetical examples to illustrate your thinking. Response Guideline Post your response of 1-3 paragraphs (about 100-200 words) by the due date for this discussion assignment, and then reply to at least two initial responses of your peers during the remainder of the unit, particularly focusing on responses that might differ from your own. Also respond appropriately to anyone who posts questions against your own postings. Discuss the content! Keep responses focused on the substance of the issue, not simply on agreeing with a comment or encouraging each other.
Mathematics
1 answer:
Triss [41]2 years ago
8 0

Answer:

Since the name indicates Minimum Variance Unbiased Estimator-first of all it is a parameter estimator. Secondly, it is an unbiased estimator so that the sample is carried out randomly. I.e. whenever a sample is chosen, there is no personal bias.

Then we can consider more than one sample-based unbiased estimator but sometimes they can vary in variation. But we have always intended to select an estimator that has minimal variance.

Therefore if the unbiased estimator has minimal variation between all unbiased class estimators then it is known as a good estimator.

The advantage of MVUE is that it is impartial and has a minimal variance of all unbiased estimators amongst the groups.

At times we get an estimator such as MLE which is not unbiased because the sample can be personally biased. Now let us assume an instructor needs to find the lowest marks in a physics class. Presume an instructor picks a sample and interprets the lowest possible marks.

Again the mistake could be that the instructor may choose his favorite sample learners because the sample might not be selected randomly. Therefore it is important to select an unbiased estimate with a minimum variance.

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Pls help me thanks :)
Lesechka [4]
Answer:
Do 7 -divided by- 1/2



Step-By-Step Explanation

If you do that u will get ur answer.
6 0
2 years ago
Kate and Jean paint a house together in 6 days. If they work alone, Kate takes 5 fewer days than Jean would take to do the same
navik [9.2K]
X = number of days it would take Kate to paint the house by herself. .
<span>x+5 = number of days it would take Jean to paint the house by herself.</span>
<span>Together, they paint the house in 6 days: </span>
<span>1/x + 1/(x+5) = 1/6 </span>
<span>Multiply both sides by 6x(x+5) </span>
<span>6(x+5) + 6x = x(x+5) </span>
<span>12x + 30 = x^2 + 5x </span>
<span>x^2 − 7x − 30 = 0 
</span>therefore the answer is A.

4 0
3 years ago
Read 2 more answers
For problem 5, use the ordered pairs to answer the following question. MUST SHOW YOUR WORK FOR FINDING SLOPE.
Firlakuza [10]

Answer:

graph them and then see if they intersect(but if you notice that the coordss of the second line are all smaller than the coords of the first line, meaning that they wont be touching at all)

Step-by-step explanation:

7 0
3 years ago
The bus will leave in 7 minutes. what time will it leave?
hjlf

Answer:

1:52

Step-by-step explanation:

The clock reads 1:45 so simply add 7 minutes to that

3 0
2 years ago
Read 2 more answers
One morning, John drive 5 hours before stopping to eat. After lunch, he. increased his speed by 10 mph. If he completed a 500-mi
Marrrta [24]
So  he drove 5hrs, before lunch, now, he was going at speed, say "r", after he ate, he sped up by 10mph, so, his rate is whatever "r" is, plus 10, or " r + 10 ", after lunch

we know the whole trip took 10hrs, so, is 5hrs before lunch and 5hrs after lunch

we also know the whole trip was 500miles, so if he drove, say "d" miles before lunch, after lunch he drove the slack after lunch, or " 200 - d "

recall, your d = rt, distance = rate * time

\bf \begin{array}{lccclll}&#10;&distance&rate&time\\&#10;&-----&-----&-----\\&#10;\textit{before lunch}&d&r&5\\&#10;\textit{after lunch}&500-d&r+10&5&#10;\end{array}&#10;\\\\\\&#10;&#10;\begin{cases}&#10;\boxed{d}=5r\\&#10;500-d=(r+10)5\\&#10;----------\\&#10;500-\boxed{5r}=(r+10)5&#10;\end{cases}&#10;\\\\\\&#10;\cfrac{500-5r}{5}=r+10\implies 100-r=r+10

and I'm sure you know what that is
6 0
3 years ago
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