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const2013 [10]
3 years ago
7

Explain and discuss why engineers usually want the minimum variance unbiased estimator achieved by using the MVUE in making engi

neering decisions, and impacts might be seen if another estimator is chosen at times? Try to use (MVUE). What benefits are what risks or hypothetical examples to illustrate your thinking. Response Guideline Post your response of 1-3 paragraphs (about 100-200 words) by the due date for this discussion assignment, and then reply to at least two initial responses of your peers during the remainder of the unit, particularly focusing on responses that might differ from your own. Also respond appropriately to anyone who posts questions against your own postings. Discuss the content! Keep responses focused on the substance of the issue, not simply on agreeing with a comment or encouraging each other.
Mathematics
1 answer:
Triss [41]3 years ago
8 0

Answer:

Since the name indicates Minimum Variance Unbiased Estimator-first of all it is a parameter estimator. Secondly, it is an unbiased estimator so that the sample is carried out randomly. I.e. whenever a sample is chosen, there is no personal bias.

Then we can consider more than one sample-based unbiased estimator but sometimes they can vary in variation. But we have always intended to select an estimator that has minimal variance.

Therefore if the unbiased estimator has minimal variation between all unbiased class estimators then it is known as a good estimator.

The advantage of MVUE is that it is impartial and has a minimal variance of all unbiased estimators amongst the groups.

At times we get an estimator such as MLE which is not unbiased because the sample can be personally biased. Now let us assume an instructor needs to find the lowest marks in a physics class. Presume an instructor picks a sample and interprets the lowest possible marks.

Again the mistake could be that the instructor may choose his favorite sample learners because the sample might not be selected randomly. Therefore it is important to select an unbiased estimate with a minimum variance.

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How do i write 14 ten thousands and 12 thousands in standard<br> form
Burka [1]
In standard form:
answer- 14,000 and 12,000

Example
←LEFT 12,000
                 ↑
   comma(THOUSANDS PLACE)

ten thosands is the second number after the comma(thousands) to the left
8 0
3 years ago
Emilio works for the parks department of West Palm City. He tracked how many emails the
MissTica

Answer:

The answer is 50%.

Step-by-step explanation:

I did the question on IXL, and got it right.

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3 years ago
Solve the equation x/4 - 7 = y for x
expeople1 [14]

Answer:

x = 4y + 28

Step-by-step explanation:

x/4 - 7 = y

+7              +7

x/4 = y + 7

× 4             × 4

x = 4y + 28

7 0
3 years ago
Read 2 more answers
4. 9d - 5 = 4<br><br> What does d =<br> 5. 6-3w=-27 what does w =<br> 6. -4= q/8-19 what does q =
trapecia [35]

Answer:

4) d = 1

5) w = 11

6) q = 120

Step-by-step explanation:

<em>4)</em> 9d - 5 = 4

Adding 5 on both the sides ,

=  > 9d - 5 + 5 = 4 + 5

=  > 9d = 9

Dividing both the sides by 9 ,

=  >  \frac{9d}{9}  =  \frac{9}{9}

=  > d = 1

<em>5)</em> 6 - 3w =  - 27

Substracting 6 from both the sides ,

6  - 3w - 6 =  - 27 - 6

=  >  - 3w =  - 33

Dividing both the sides by -3 ,

=  >  \frac{ - 3w}{ - 3}  =  \frac{ - 33}{ - 3}

=  > w = 11

<em>6)</em> - 4 =  \frac{q}{8}  - 19

Adding 19 on both the sides ,

\frac{q}{8}  - 19 + 19 = - 4 + 19

=  >  \frac{q}{8}  = 15

Multiplying both the sides by 8 ,

=  >  \frac{q}{8}  \times 8 = 15 \times 8

=  > q = 120

6 0
3 years ago
You want to create a 99% confidence interval with a margin of error of .5. Assuming the population standard deviation is equal t
miss Akunina [59]

Answer:

Sample size minimum is 60

Step-by-step explanation:

given that you want to create a 99% confidence interval with a margin of error of .5.

The population  standard deviation is equal to 1.5

i.e. \sigma = 0.5

Confidence level = 99%

Since population std deviation is known, we can use Z critical value for finding margin of error

Z critical value for 99% = 2.58

Margin of error = 2.58*\frac{1.5}{\sqrt{n} }

Equate this to 0.5 and solve for n

2.58*\frac{1.5}{\sqrt{n} }=0.5\\\sqrt{n} =7.74\\n =59.90\\n=60

8 0
3 years ago
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