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3 years ago

PLEASE HELP URGENT!! MATH!!!

Mathematics

1 answer:

aliina [53]3 years ago

5 0

Answer:

Oh god....

Step-by-step explanation:

copy and paste the question into the braainly search bar, if that's doesn't work google it.

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(6x+7) - (9x-5) HELP

ycow [4]

Answer:-3x+12

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Is 2/15 a repeating decimal or a terminating decimal?

lubasha [3.4K]

2/15 = 0.1333333333... It is a repeating decimal, because a terminarog decimal ends, and this doesn't end.

6 0

3 years ago

Suppose you do an analysis of the starting salaries of 100 recent Lehman graduates. You find that the average starting salary is

madreJ [45]

Answer:

a) (59180,60820)

b) (59020,60980)

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $60,000

Standard Deviation, σ = $5,000

Sample size, n = 100

a) 90% critical values

$\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$z_{critical}\text{ at}~\alpha_{0.10} = 1.64$

$60000 \pm 1.64(\frac{5000}{\sqrt{100}} ) = 60000 \pm 820 = (59180,60820)$

b) 95% critical values

$\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

$60000 \pm 1.96(\frac{5000}{\sqrt{100}} ) = 60000 \pm 980= (59020,60980)$

5 0

3 years ago

Assume that body masses of Goldfinch birds follow a normal distribution with standard deviation equal to 0.04 oz. An ornithologi

il63 [147K]

Answer:

The formula to generate 70% confidence interval is: $[\overline{x} - 0.013, \overline{x} + 0.013]$ , in which $\overline{x}$ is the sample mean.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.7}{2} = 0.15$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.15 = 0.85$ , so Z = 1.037.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Assume that body masses of Goldfinch birds follow a normal distribution with standard deviation equal to 0.04 oz.

This means that $\sigma = 0.04$ .

Sample of 10 birds:

This means that $n = 10$ .

The margin of error is of:

$M = z\frac{\sigma}{\sqrt{n}}$

$M = 1.037\frac{0.04}{\sqrt{10}}$

$M = 0.013$

The lower end of the interval is the sample mean of $\overline{x}$ subtracted by M.

The upper end of the interval is the sample mean of $\overline{x}$ added to M.

Then, the formula to generate 70% confidence interval is: $[\overline{x} - 0.013, \overline{x} + 0.013]$ , in which $\overline{x}$ is the sample mean.

8 0

3 years ago

Solve the inequality 3x-1>-6x

Ghella [55]

Answer:

x > 1/9

Step-by-step explanation:

Given that:

3x-1>-6x

Adding 6x + 1 on both sides we get

3x-1 + 6x + 1>-6x + 6x +1

3x + 6x > 1

Adding both variables

9x > 1

Dividing both sides b 9 we get

9x/9 > 1/9

x > 1/9

I hope it will help you!

3 0

4 years ago