A factory makes 3,000 plastic forks per hour. How many plastic forks will the factory make in 6 hours?
2 answers:
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Check the picture attached.
let m(VTI)= m(ITU)=a and let m(VUI)= m(IUT)=b
Then, in triangle TUV:
2a+2b+c=180°
2(a+b)+c=180°
c=180°-2(a+b)
In triangle TUI:
a+b+109°=180°
a+b=180°-109°=71°
substitute in c=180°-2(a+b):
c=180°-2(a+b)=180°-2*71°=180°-142°=38°
let m(VTI)= m(ITU)=a and let m(VUI)= m(IUT)=b
Then, in triangle TUV:
2a+2b+c=180°
2(a+b)+c=180°
c=180°-2(a+b)
In triangle TUI:
a+b+109°=180°
a+b=180°-109°=71°
substitute in c=180°-2(a+b):
c=180°-2(a+b)=180°-2*71°=180°-142°=38°
Answer:
3 machine
Step-by-step explanation:
It is given that 6 machine each working at the same rate can complete the work in 12 days
We the has to complete in 8 days
Let we need x extra machine to complete the work in 8 days
So total number of machines =x+6
Now according to man work day equation
x=3 machine
The correct question in the attached figure
we know that
the scale is 1 in (scale drawing)= (1/2) foot (actual)-----> 1/(1/2)=2 in/ft
[scale]=[scale drawing]/[actual]
then
[scale drawing]=[scale]*[actual]
therefore
for <span>actual width of the car 8 ft
</span>[scale drawing]=[2 in/ft]*[8 ft]=16 in
<span>
the answer is 16 in
</span><span>
</span>
we know that
the scale is 1 in (scale drawing)= (1/2) foot (actual)-----> 1/(1/2)=2 in/ft
[scale]=[scale drawing]/[actual]
then
[scale drawing]=[scale]*[actual]
therefore
for <span>actual width of the car 8 ft
</span>[scale drawing]=[2 in/ft]*[8 ft]=16 in
<span>
the answer is 16 in
</span><span>
</span>