I think is D hopefully is right
Answer:
-692784311700
Step-by-step explanation:
Answer:
Its the first Graph the one with the open circle at 3 and going right.
Step-by-step explanation:
Answer:
x= -2-√11. or. x= -2 + √11
Step-by-step explanation:
solving quadratic equation by completing the square
x^2+4x-7=0
x^2+4x=7
x^2+4x + (4/2)^2=7 + (4/2)^2 ( adding (1/2 coefficient of x)^2 on both sides
x^2+4x + 4=7 + 4
x^2+4x + 4=11. factorize(x^2+4x + 4) into (x + 2)^2
(x + 2)^2=11
√(x + 2)^2= + - √11
x + 2 = + - √11
there are two different solution .
x + 2 = -√11. or x + 2 = + √11.
x= -2-√11. or. x= -2 + √11.
Answer:
y = x + 15
Step-by-step explanation:
If two lines are perpendicular to each other, they have opposite slopes.
The first line is y = - x - 2. Its slope is -1. A line perpendicular to this will have a slope of 1.
Plug this value (1) into your standard point-slope equation of y = mx + b.
y = 1x + b or y = x + b
To find b, we want to plug in a value that we know is on this line: in this case, it is (-5, 10). Plug in the x and y values into the x and y of the standard equation.
10 = (-5) + b
Simplify.
10 = -5 + b
Now, add 5 to both sides to isolate b.
15 = b
Plug this into your standard equation.
y = x + 15
This equation is perpendicular to your given equation (y = -x - 2) and contains point (-5, 10)
Hope this helps!