Answer:
10(q-3)
last option
please brainliest me btw
Step-by-step explanation:
The expression states 10q-30
The GCF is 10 (30 GCF by 10 Is 10)
Factor out 10
After, divide all the terms by 10
10 (10q/10) - 30/10
Simplify this and we get
10(q-3)
so in conclusion, it is the last option.
I actually believe that the answer is A
Answer:
Step-by-step explanation:
We are given that
y(0)=0
y'(0)=1
By comparing with
We get
q(x)=0
p(x),q(x) and g(x) are continuous for all real values of x except 3.
Interval on which p(x),q(x) and g(x) are continuous
and (3,
By unique existence theorem
Largest interval which contains 0=
Hence, the larges interval on which includes x=0 for which given initial value problem has unique solution=