Given:
Desmond deposits $ 50 monthly.
Yearly he deposits = $50×12 = $ 600
Rate of interest compounded monthly = 4.7%
To find the amount he will receive after 10 years and the rate of change the value of his account after 10 years.
Formula

where,
A be the final amount
P be the principal
r be the rate of interest
t be the time and
n be the number of times the interest is compounded.
Now,
Taking,
P = 600, r = 4.7, n = 12, t = 10 we get,

or, 
or, 
Now,
At starting he has $ 600
At the end of 10 years he will be having $ 959.1
So,
The amount of change in his account = $ (959.1-600) = $ 359.1
Therefore the rate of change = 
= 59.85%
Hence,
a) His account will contain $ 959.1 after 10 years.
b) The rate of change in his account is 59.85% after 10 years.
Answer:
The amount of change in the balance of the account is an increase of $3160.57.
Step-by-step explanation:
i) first deposit is given as $1250
ii) second deposit is given as $3040.57
iii) first withdrawal is given as $400
iv) second withdrawal is given as $400
v) third withdrawal is given as $400
vi) first penalty removed is $35
vii) second penalty removed is $35
viii) therefore the change to the balance is given by
$1250 + $3040.57 - $400 - $400 - $400 + $35 + $35 = $3160.57
viii) Therefore the amount of change in the balance of the account is an increase of $3160.57.
Question 11 is C and also question 2 is A
Answer:
135
Step-by-step explanation:
Well 3 friends and 45 dollars each
45*3=135