are you asking for the 9th term or the 10th term?
Answer:
The vertex for parabola y²=4ax is (0,0)
and for (y-k) ²= 4a(x+h), vertex is (h, k).
But you have not given the equation of parabola in the equation.
The options Patel has to solve the quadratic equation 8x² + 16x + 3 = 0 is x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot.
<h3>Quadratic equation</h3>
8x² + 16x + 3 = 0
8x² + 16x = -3
8(x² + 2x) = -3
- Using completing the square
8(x² + 2x + 1) = -3 + 8
8(x² + 1) = 5
(x² + 1) = 5/8
- Taking the square root of both sides
(x + 1) = ± √5/8
x = -1 ± √5/8
Therefore,
x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot
Learn more about quadratic equation:
brainly.com/question/1214333
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Answer:
y = 2
Step-by-step explanation:
Since the line is parallel to the x-axis,
the gradient, m = 0
From the point, we know that
x = 5
y = 2
So y = 2 is the line that parallel to x-axis
volume = 4/3 x PI x r^3
r = 10/2 =5
V = 4/3 x 3.14 x 5^3 = 523.333
523.3 cubic inches
