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Pavlova-9 [17]
2 years ago
5

A plant population produces many seeds. that if a population of plants is currently 30 individuals, and rmax= 12 plants/month, t

he carrying capacity is in meadow is 40 plants. what is their dn/dt in this logistic growth situation?
Biology
1 answer:
LiRa [457]2 years ago
5 0

Answer:

\frac{dN}{dt} = 14130

Explanation:

Logistic growth is a measure of continuous growth of a population of individuals in such an environment where the resources are limited. Such type of growth pattern has a characteristic growth curve which is S-shaped or sigmoidal.

The equation for logistic growth is as follows -

Change in population size = \frac {dN}{dt} = rN(K- \frac {N}{K})

Where,

N = size of population

r = intrinsic rate of increase

K = carrying capacity

The values of r, N and K are given in the question as 12, 30 and 40 respectively.

So,

\frac{dN}{dt} = 12 \times 30(40 - \frac{30}{40}) = 14130

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Answer/Explanation:

<h3>∴ ║ Living Things Need Energy ║∴</h3>

The ability to obtain and use energy is one of the eight characteristics of all living things.  Scientists classify organisms based on how they get their energy: autotrophs or heterotrophs.  Organisms are divided into three main groups- the producers, the consumers and the decomposers.  

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Consumers cannot make their own food.  Instead, they get their energy by eating other organisms.  These are also called heterotrophs.  There are many types of consumers.  Herbivores, such as grasshoppers and prairie dogs, only eat producers.  Carnivores eat animals.  Coyotes, badgers, and falcons are all carnivores.  Organisms that eat both producers and other consumers are known as omnivores.  Most humans are omnivores.  Scavengers are a special type of omnivore.  They eat dead plants and animals.  Vultures and many insects are common scavengers.  

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