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Pavlova-9 [17]
2 years ago
5

A plant population produces many seeds. that if a population of plants is currently 30 individuals, and rmax= 12 plants/month, t

he carrying capacity is in meadow is 40 plants. what is their dn/dt in this logistic growth situation?
Biology
1 answer:
LiRa [457]2 years ago
5 0

Answer:

\frac{dN}{dt} = 14130

Explanation:

Logistic growth is a measure of continuous growth of a population of individuals in such an environment where the resources are limited. Such type of growth pattern has a characteristic growth curve which is S-shaped or sigmoidal.

The equation for logistic growth is as follows -

Change in population size = \frac {dN}{dt} = rN(K- \frac {N}{K})

Where,

N = size of population

r = intrinsic rate of increase

K = carrying capacity

The values of r, N and K are given in the question as 12, 30 and 40 respectively.

So,

\frac{dN}{dt} = 12 \times 30(40 - \frac{30}{40}) = 14130

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