A line segment has endpoints at (3, 2) and (2, –3). Which reflection will produce an image with endpoints at (3, –2) and (2, 3)?
2 answers:
Answer:
Option A - a reflection of the line segment across the x-axis
Step-by-step explanation:
Given : A line segment has endpoints at (3, 2) and (2, –3).
To find : Which reflection will produce an image with endpoints at (3, –2) and (2, 3)
Solution : To determine the reflection we can see in the graph attached that the reflection is towards the x-axis
Therefore, A reflection of line segment with endpoints at (3, 2) and (2, –3) have a reflection of the line segment across the x-axis with end points (3, –2) and (2, 3)
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Given:
The length of the rectangle = 16 ft
The width of the rectangle = 12 ft
The diameter of the semicircle = 12 ft
To find the area of the given figure.
Formula
where,
be the area of the given figure
be the area of the rectangle
be the area of the semicircle.
- The area of the rectangle =
where, l be the length and b be the width
- Area of the semicircle =
, r be the radius of the semicircle.
Now,
The radius of the semicircle r = 6 ft
Putting, r=6, l=16 and b= 12 we get,
sq ft
or, sq ft
sq ft
or, sq ft
So,
sq ft
= 248.52 sq ft
Rounding off to the nearest tenth, we get;
A=248.5 sq ft.
Hence,
The area of the composite figure is 248.5 sq ft.
Answer: A(W) = 100W -
Step-by-step explanation:
The formula for calculating the perimeter is given as :
P = 2 ( L + W )
the perimeter is given as 200 , that is
200 = 2 ( L + W )
Dividing through by 2 , we have
100 = L + W
Make L the subject of the formula ;
L = 100 - W
The formula for the area is given as Length x width , substituting the values , we have :
A = LW , since , L = 100 - W , we have
A = (100- W) (W)
A = 100W -
Therefore :
A(W) = 100W -