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bazaltina [42]
2 years ago
6

Draw a cross section of a peach, and label the structures. What parts of the flower give rise to these structures

Biology
1 answer:
ICE Princess25 [194]2 years ago
6 0

Answer:

exocarpo  is synonymous with exocarp

endocarpo is synonymous with endocarp

mesocarpo is synonymous with mesocarp

semilla is synonymous with seed

Explanation:

In phase one, the plant's ovary begins to grow abruptly, this is where the embryo and endosperm affect their size, but if this ovarian growth is interrupted by an external factor, it determines the size of the future.

Then, the embryo and the endosperm could grow and undergo a process called sclerification, which is the hardening of the interior of the fruit, that is to say, the future formation of the seed or vulgarly called "pit". .

After this, the mesocarp, which is what is called the fleshy body or subglobose edible drupe, begins to grow.

The growth of the mesocarp is what gives the volume, weight and body to the fruit, so that after maturation it exceeds the strength of the branch and it falls from the tree.

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availability of resources.

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3 years ago
Gold has a specific heat of 0.129 J/(g×°C). How many joules of heat energy are required to raise the temperature of 15 grams of
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Answer:

\boxed {\boxed {\sf 121.905 \ J  }}

Explanation:

We are asked to find the energy given mass, specific heat, and change in temperature. Therefore, we must use this formula;

q= mc \Delta T

The mass is 15 grams and the specific heat is 0.129 J/(g×°C). Let's calculate the change in temperature.

  • ΔT= final temperature - initial temperature
  • ΔT= 85 °C- 22°C = 63°C

Now we know all the values:

m= 15 \ g \ \\c= 0.129 \ J / (g* \textdegree C) \\\Delta T= 63 \ \textdegree C

Substitue the values into the formula.

q= (15 \ g)( 0.129 \ J / (g* \textdegree C)) ( 63 \ \textdegree C)

Multiply the first numbers together. The grams will cancel.

q= (1.935 \ J/ \textdegree C) ( 63 \ \textdegree C)

Multiply again, this time the degrees Celsius cancels.

q= 121.905 \ J

<u>121.905 Joules</u> are required.

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Answer:

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Explanation:

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