Answer:
6 miles
Step-by-step explanation:
From the above question:
Stan ran 4 and StartFraction 7 Over 10 EndFraction miles
The number of miles stan ran =
4 7/10 miles
We are also told that this number of miles was 1 and StartFraction 3 Over 10 EndFraction fewer miles than Matt ran.
Let the number of miles Matt ran = m
Hence,
4 7/10 miles = m - 1 3/10
m = 4 7/10 + 1 3/10
m = (4 + 1) + ( 7/10 + 3/10)
m = 5 + (7 + 3/10)
m = 5 + (10/10)
m = 5 + 1
m = 6 miles
Therefore, the number rod miles Matt ran was 6 miles
Answer:
1.50
Step-by-step explanation:
Your answer is C. Think of the x axis as the ground.
From Newton’s Second Law of Motion, the force needed to accelerate a moving object of mass m at acceleration a is given by ;
F = ma
In this case, m = 5kg, a = 6m/s^2 and we want to find F
F = 5 x 6
F = 30N
Therefore, a force of 30N is needed to accelerate a 5kg object at 6m/s^2.
Times -7 by everything in the parentheses. so
-7 times 5y=-35y
-7 times -2u=14u
-7 times -5 = 35
therefore 35y+14u+35
