Question

A circle with center C (4, -2) contains the point D(8,1) what is the equation for the line perpendicular to the radius of the circle passing through point C

Answer 1

Answer:

Step-by-step explanation:

slope of line passing through C and D is

$m=\frac{1+2}{8-4} =\frac{3}{4}$

slope of line perpendicular to CD=-4/3

reqd. eq. of line through C(4,-2) is

$y+2=-\frac{4}{3} (x-4)\\3y+6=-4x+16\\4x+3y=10$