Answer:
Step-by-step explanation:
slope of line passing through C and D is
slope of line perpendicular to CD=-4/3
reqd. eq. of line through C(4,-2) is
6/10
2 groups of 3/10 =
2 × 3/10 =
a
9
6+x, when x = 3
6+(3)
6+3=9
You can see the attached picture