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svlad2 [7]
3 years ago
5

Solve x2 + 10x + 7 = 0 by completing the square. Which equation is used in the process?

Mathematics
2 answers:
Svetach [21]3 years ago
8 0

Answer:

(x+5)^2=18

Step-by-step explanation:

Twas on my final

BaLLatris [955]3 years ago
5 0
x^2+10x+7=0\ \ \ \ |subtract\ 7\ from\ both\ sides\\\\x^2+2x\cdot5=-7\ \ \ |add\ 5^2\ to\ both\ sides\\\\x^2+2x\cdot5+5^2=-7+5^2\ \ \ |use\ a^2+2ab+b^2=(a+b)^2\\\\(x+5)^2=-7+25\\\\(x+5)^2=18\iff x+5=\pm\sqrt{18}\\\\x+5=-\sqrt{18}\ or\ x-5=\sqrt{18}\\\\x+5=-\sqrt{9\cdot2}\ or\ x-5=\sqrt{9\cdot2}\\\\x+5=-\sqrt9\cdot\sqrt2\ or\ x-5=\sqrt9\cdot\sqrt2\\\\x+5=-3\sqrt2\ or\ x-5=3\sqrt2\ \ \ |subtract\ 5\ from\ both\ sides\\\\\boxed{x=-5-3\sqrt2\ or\ x=-5+3\sqrt2}
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Answer:

  a) 5, 6

  b) 8, 9

  c) 9, 10

Step-by-step explanation:

It is useful to know the squares of small integers:

  5² = 25

  6² = 36

  7² = 49

  8² = 64

  9² = 81

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Then the problem becomes one of identifying the perfect squares the given number lies between

  a)  25 < 35 < 36   ⇒   5 < √35 < 6

  b) 64 < 67 < 81   ⇒   8 < √67 < 9

  c) 81 < 93 < 100   ⇒   9 < √93 < 10

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4 years ago
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Gennadij [26K]
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6 0
3 years ago
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OLga [1]

Answer:

  1. d, series and sequence diverge
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Step-by-step explanation:

<h3>1.</h3>

The sequence terms have a common difference of -5/8. That make it a non-trivial arithmetic sequence, so it diverges.

The series is the sum of terms of the sequence. Any non-trivial arithmetic series diverges.

(A "trivial" arithmetic series has a first term of 0 and a common difference of 0. It is the only kind of <em>arithmetic</em> series that doesn't diverge.)

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<h3>2.</h3>

The terms of the series have a common ratio of -2. That makes it a geometric series. The ratio magnitude is greater than 1, so the series diverges.

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<h3>3.</h3>

A sequence will converge only if the terms have a common difference of 0 or a common ratio with a magnitude less than 1. Of the offered choices, only C and E will converge:

  c. geometric, r = 3/5

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_____

<em>Additional comment</em>

The convergence criteria stated for problem 3 applies only to arithmetic and geometric sequences. There are many other kinds of sequences that converge, but these are the kinds being considered in this problem set.

3 0
2 years ago
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Fudgin [204]

Answer:

Infinitely many solutions

Step-by-step explanation:

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