Explanation: We know that: small diameter = 2 * 10^-2 in large diameter = 6 * 10^-2 in
We want to know how many times larger is the thin diameter compared to the large one. We will do this as follows: large diameter = k * small diameter where k is the number of times that we want to find 6 * 10^-2 = k * 2 * 10^-2 k = (6 * 10^-2) / (2 * 10^-2) k = 3
This means that the large diameter is 3 times the small one.
Move your decimal until you have one non-zero number left of your deciaml point the number of times you moved you decimal to the left will be the exponent you put attached to a ten.
