Answer:
150
Step-by-step explanation:
300-150
Answer:
so, the figure here is a cylinder with a semi sphere on the top, we know the height of whole structure, and the radius of the semi sphere, which is the same as the radius of the cylinder (you can see it because the radius of the semisphere is constant, and you can thin on it as half a sphere over a cylinder).
First, the cylinder will be the structure without the semi sphere, so his height will be te total height minus the radius of the semi sphere, which is 0.9μm.
so now we know the height and the radius of the cylinder, the surface or the sides of it is 2*3.14*r*h = 2*3.14*0.9μm*0.1μm = 0.5662
.
Answer:
The fraction of smoothies sold were either banana or strawberry is ![\frac{11}{12}.](https://tex.z-dn.net/?f=%5Cfrac%7B11%7D%7B12%7D.)
Step-by-step explanation:
Given:
Of the smoothies sold yesterday at Marlins smoothie shop, 5/6 were banana and another 1/12 were strawberry.
Now, to find the fraction of the smoothies sold were either banana or strawberry.
Fraction of smoothie were of banana = ![\frac{5}{6} .](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B6%7D%20.)
Fraction of smoothie were of strawberry = ![\frac{1}{12} .](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B12%7D%20.)
Now, to get the fraction smoothies sold were either banana or strawberry by adding both the fractions of banana and strawberry:
![\frac{5}{6} +\frac{1}{12} \\\\=\frac{10+1}{12} \\\\=\frac{11}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B6%7D%20%2B%5Cfrac%7B1%7D%7B12%7D%20%5C%5C%5C%5C%3D%5Cfrac%7B10%2B1%7D%7B12%7D%20%5C%5C%5C%5C%3D%5Cfrac%7B11%7D%7B12%7D)
Therefore, the fraction of smoothies sold were either banana or strawberry is ![\frac{11}{12}.](https://tex.z-dn.net/?f=%5Cfrac%7B11%7D%7B12%7D.)
Answer:
It would take 50 minutes
Step-by-step explanation:
<u>Distance, velocity and time</u>
The speed is the rate at which the distance changes with respect to time. If x is the distance, t is the time, the speed v can be obtained by
![\displaystyle v=\frac{x}{t}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20v%3D%5Cfrac%7Bx%7D%7Bt%7D)
We know the trip takes 40 minutes when traveling at 50 miles/hour. The distance can be determined by isolating x in the above equation
![x=vt](https://tex.z-dn.net/?f=x%3Dvt)
The given time is expressed in minutes, we need to convert it to hours. 40 minutes is
. The distance is
![\displaystyle x=(50)(0.666..)=33.33\ miles](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3D%2850%29%280.666..%29%3D33.33%5C%20miles)
If the speed was 40 miles/hour, the same distance would be covered in t hours, taken from the above equation as
![\displaystyle t=\frac{x}{v}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20t%3D%5Cfrac%7Bx%7D%7Bv%7D)
![t=\frac{33.33}{40}=0.8333\ hours = 0.83333*60= 50\ minutes](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B33.33%7D%7B40%7D%3D0.8333%5C%20hours%20%3D%200.83333%2A60%3D%2050%5C%20minutes)