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Semmy [17]
3 years ago
12

Can someone please tell me how to expand and simplify 4(x+1)^2?

Mathematics
1 answer:
siniylev [52]3 years ago
4 0

Expand the binomial first, then distribute the 4:

4 (<em>x</em> + 1)² = 4 (<em>x</em> ² + 2<em>x</em> + 1)

… = 4•<em>x</em> ² + 4•2<em>x</em> + 4•1

… = 4<em>x</em> ² + 8<em>x</em> + 4

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Answer:

Answer:

Domain = {x /x ≥ -7}

Step-by-step explanation:

The given function y =

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First let's find the domain. x + 7 must be greater than or equal to 0.

x + 7 ≥ 0

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x ≥ -7

Domain = {x /x ≥ -7}

Hope this will help you.

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Solve 4 by 216 raise to minus 2 by 3 + 1 by 256 raise to 3 by 4 + 2 by 243 raise to 1 by 5​
olchik [2.2K]

Answer:

214....

Step-by-step explanation:

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The given expression can be written as:

4/(216)-2/3+1/(256)-3/4+2/(243)-1/5

This expression has three terms.

Notice that the exponents are negative:

We will change the division into multiplication so that the exponents will become positive;

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If we multiply 6 three times it will give us 6^3=6*6*6=216

If we multiply 4 four  times it will give us 4^4=4*4*4*4=256

If we multiply 3 five times it will give us 3^5=3*3*3*3*3=243

So we will write it as:

=4*(6^3)^2/3+ 1(4^4)3/4 +2(3^5)^1/5

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7 0
3 years ago
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goldenfox [79]

Answer:

\sqrt{2 + 1} < \sqrt{2 + 2}

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\sqrt{2 + 1} < \sqrt{2 + 2}

5 0
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