QUESTION 1
We want to solve,

We factor the denominator of the fraction on the right hand side to get,

This implies


We multiply through by LCM of


We expand to get,

We group like terms and equate everything to zero,

We split the middle term,

We factor to get,





But

is not in the domain of the given equation.
It is an extraneous solution.

is the only solution.
QUESTION 2

We add x to both sides,

We square both sides,

We expand to get,

This implies,

We solve this quadratic equation by factorization,





But

is an extraneous solution
The extraneous solution of startroot 4 x 41 endroot = x 5 will be A. -8.
<h3>What is an extraneous solution?</h3>
It should be noted that an extraneous solution simply means a root of a transformed equation which isn't part of the original equation.
✓4x + 41 = x + 5
Square both sides
4x + 41 = x² + 10x + 25
x² + 6x - 16
x(x + 8) - 2(x + 8) = 0
x + 8 = 0
x= 0 + 8 = 8
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Answer:you divide 90 by 4
Step-by-step explanation:
Answer:
1150$
Step-by-step explanation:
2800$-500$=2300$÷2=1150$
hope this helped ; )
x = 6
Step-by-step explanation:
2 - 12 × x = -70
= -12x +2 = -70