<h3>
Answer:</h3>
A and C
<h3>
Step-by-step explanation:</h3>
Given:
-60x+32 = Qx+P
Find:
Which values of P and Q result in an equation with no solutions? Choose all answers that apply:
(Choice A) A Q=-60 P=60
(Choice B) B Q=32 P=60
(Choice C) C Q=-60 P=−32
(Choice D) D Q=32 P=−60
Solution:
The equation will have no solution if it reduces to ...
0 = (non-zero constant)
If we add 60x-32 to both sides, we get
0 = 60x +Qx + P-32
0 = (Q+60)x +(P-32)
The x-term must be zero, so Q+60 = 0, or Q = -60.
The constant term must be non-zero, so P-32 ≠0, or P ≠ 32.
The appropriate answer choices are those with Q=-60 and P≠32, A and C.
Answer:24
Step-by-step explanation:
Answer: 7+0.7+0.05
Since 7 is in the ones place it goes in front of the decimal. .7 is in the tenth place because it's behind the decimal. .05 is also behind the decimal so it's in the hundredths place.
2 and 1/4 miles is how far Mary walks around the track. This is because she walks for 15 minutes before Jerry gets there, which is 0.75 miles at 3mph. Then Jerry goes for 2 miles, which is half an hour. Half an hour is double 15 minutes, so it's double 0.75 miles. So 0.75 plus 1.5 = 2.25 Mark me brainliest :3
False
b could be the logarithm of a rational number to the base a. For example,
will be irrational, but π^b = 4, a rational number
