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Sever21 [200]
3 years ago
5

Solve for x.

-7)-2=3" alt="15log_{8} (-2x-7)-2=3" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
vova2212 [387]3 years ago
5 0

Answer: x=-4.5

Step-by-step explanation:

Add 2 to both sides of the equation and divide both sides of the equation by 15. Then:

15log_{8} (-2x-7)-2+2=3+2\\15log_{8} (-2x-7)=5\\\\\frac{15log_{8} (-2x-7)}{15}=\frac{5}{15}\\\\log_{8}(-2x-7)=\frac{1}{3}

Apply base 8 to both sides of the equation:

8^{log_{8}(-2x-7)}=8^{\frac{1}{3}}\\\\-2x-7=8^{\frac{1}{3}}

Solve for "x", then you get:

-2x-7=8^{\frac{1}{3}}\\\\-2x=\sqrt[3]{8}+7\\\\ x=\frac{\sqrt[3]{8}+7}{-2}\\\\x=-4.5

 

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The least common multiple of two numbers is 60. the prime factorization of one number is 3 times 5. what is the prime factorizat
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The first number would be 3×5=15. 
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3 years ago
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3 years ago
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7 0
3 years ago
Use the remainder theorem to find P (-3) for P (x) = x to the power of 4 + 4x to the power of 3 - 3x - 7
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5 0
3 years ago
May someone help me with this question please anyone please
djverab [1.8K]
5;\ 5;\ 5;\ 5;\ 7;\ 9\\\\\overline{x}=\dfrac{5+5+5+5+7+9}{6}=\dfrac{36}{6}=6\\\\\delta^2=\dfrac{(x_1-\overline{x})^2+(x_2-\overline{x})^2+(x_3-\overline{x})^2+...+(x_n-\overline{x})^2}{n}\\\\\delta^2=\dfrac{(5-6)^2+(5-6)^2+(5-6)^2+(5-6)^2+}{6}
\dfrac{+(7-6)^2+(9-6)^2}{6}\\\\\delta^2=\dfrac{(-1)^2+(-1)^2+(-1)^2+(-1)^2+1^2+3^2}{6}=\dfrac{14}{6}=\dfrac{7}{3}

standard\ deviation:\\\\\sqrt{\delta^2}=\sqrt{\dfrac{7}{3}}=\dfrac{\sqrt7}{\sqrt3}=\dfrac{\sqrt7\cdot\sqrt3}{\sqrt3\cdot\sqrt3}=\boxed{\dfrac{\sqrt{21}}{3}}\approx\boxed{1.53}
4 0
3 years ago
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