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Sever21 [200]
3 years ago
5

Solve for x.

-7)-2=3" alt="15log_{8} (-2x-7)-2=3" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
vova2212 [387]3 years ago
5 0

Answer: x=-4.5

Step-by-step explanation:

Add 2 to both sides of the equation and divide both sides of the equation by 15. Then:

15log_{8} (-2x-7)-2+2=3+2\\15log_{8} (-2x-7)=5\\\\\frac{15log_{8} (-2x-7)}{15}=\frac{5}{15}\\\\log_{8}(-2x-7)=\frac{1}{3}

Apply base 8 to both sides of the equation:

8^{log_{8}(-2x-7)}=8^{\frac{1}{3}}\\\\-2x-7=8^{\frac{1}{3}}

Solve for "x", then you get:

-2x-7=8^{\frac{1}{3}}\\\\-2x=\sqrt[3]{8}+7\\\\ x=\frac{\sqrt[3]{8}+7}{-2}\\\\x=-4.5

 

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18 {x}^{2}  + 21x - 60 = 0

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6 {x}^{2}  + 7x - 20 = 0

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Move constant to R.H.S and change its sign

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Calculate the difference

2x  =  - 5

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Calculate

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