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Sever21 [200]
3 years ago
5

Solve for x.

-7)-2=3" alt="15log_{8} (-2x-7)-2=3" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
vova2212 [387]3 years ago
5 0

Answer: x=-4.5

Step-by-step explanation:

Add 2 to both sides of the equation and divide both sides of the equation by 15. Then:

15log_{8} (-2x-7)-2+2=3+2\\15log_{8} (-2x-7)=5\\\\\frac{15log_{8} (-2x-7)}{15}=\frac{5}{15}\\\\log_{8}(-2x-7)=\frac{1}{3}

Apply base 8 to both sides of the equation:

8^{log_{8}(-2x-7)}=8^{\frac{1}{3}}\\\\-2x-7=8^{\frac{1}{3}}

Solve for "x", then you get:

-2x-7=8^{\frac{1}{3}}\\\\-2x=\sqrt[3]{8}+7\\\\ x=\frac{\sqrt[3]{8}+7}{-2}\\\\x=-4.5

 

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This question is quite simple as long as you know how to do math you should ace all of your math classes..

Mathematics can get pretty complicated. Fortunately, not all math problems need to be inscrutable. Here are five current problems in the field of mathematics that anyone can understand, but nobody has been able to solve.

like...Pick any number. If that number is even, divide it by 2. If it's odd, multiply it by 3 and add 1. Now repeat the process with your new number. If you keep going, you'll eventually end up at 1. Every time.

Mathematicians have tried millions of numbers and they've never found a single one that didn't end up at 1 eventually. The thing is, they've never been able to prove that there isn't a special number out there that never leads to 1. It's possible that there's some really big number that goes to infinity instead, or maybe a number that gets stuck in a loop and never reaches 1. But no one has ever been able to prove that for certain.

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AM I BEING TO MUCH OF A SMART ALECK, I'm sorry if i am LOL.

but if you need help with another question, you can ask me :)

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