Step-by-step explanation:
You need to solve for x.
You can do that by either setting both of the equations equal to each other. or Solve each one separately and subtract the EG equation from the EW to get GW
you turn 1 and 1 over 5 into 6 over 5. then divide.
12 divided by 6 over 5 equals 10
X²/9 + y²/16 = 1
The general for mula of an ellipse is:
(x-h)²/a² + (y-k)²/b² = 1. Since h = k = 0, this ellipse
x²/9 + y²/16 = 1
passes by the center O. (Note that a = 3 and b = 4)
Moreover sin b>a so the majore axis is (on the y-axis) and a the minor axis (on the x-axis) [Its shape is as a vertical egg].
On a system of perpendicular axis that intercept in O., take on the x-axis 2 points A & B with respective coordinate A(3.0) and B(-3,0)
On the y-axis your report A'(0,+4) and B'(0,-4). So you have the vertex of the ellipse, then it's easy to draw it
To write 3.40 as a fraction you have to write 3.40 as numerator and put 1 as the denominator. Now you multiply numerator and denominator by 10 as long as you get in numerator the whole number.
3.40 = 3.40/1 = 34/10
And finally we have:
3.40 as a fraction equals 34/10 simplified we get: 3 2/5
