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hjlf
3 years ago
8

The length of a rectangular park is 20 feet longer than the width of the park. If the lenght of the park is 36 feet, what is the

width of the park?

Mathematics
1 answer:
lara [203]3 years ago
3 0

Below is a labeled rectangle:

length = w + 20

we know length is 36 so we plug that in:

36 = w + 20

We need to isolate w and to do that we must subtract 20 from both sides:

(36 - 20) = w + (20 - 20)

16 = w + 0

w = 16

width is 16 feet

Hope this helped!

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(50 points &amp; Will give brainliest)
sweet-ann [11.9K]

Answer:

x = 3 , y = 13

Step-by-step explanation:

Note that both equations is equal to y. Set the two equations equal to each other

y = 7x - 8; y = 5x - 2

7x - 8 = y = 5x - 2

7x - 8 = 5x - 2

Isolate the x. Subtract 5x and add 8 to both sides

7x (-5x) - 8 (+8) = 5x (-5x) - 2 (+8)

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Isolate the x. Divide 2 from both sides

(2x)/2 = (6)/2

x = 6/2

x = 3

---------------------------------------------------------------------------------------------------

Plug in 3 for x in one of the equations.

y = 7x - 8

y = 7(3) - 8

Simplify. Remember to follow PEMDAS.

y = 7(3) - 8

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x = 3, y = 13 is your answer

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4 0
3 years ago
What is the answer to this solution. -7r−4≥ 4r+2
tia_tia [17]

Answer:

The solution is:

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Please check the attached line graph below.

Step-by-step explanation:

Given the expression

-7r-4\ge \:4r+2

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-7r-4+4\ge \:4r+2+4

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-7r-4r\ge \:4r+6-4r

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Simplify

11r\le \:-6

Divide both sides by 11

\frac{11r}{11}\le \frac{-6}{11}

Simplify

r\le \:-\frac{6}{11}

Therefore, the solution is:

-7r-4\ge \:\:4r+2\quad \::\quad \:\begin{bmatrix}\mathrm{Solution:}\:&\:r\le \:\:-\frac{6}{11}\:\\ \:\:\mathrm{Decimal:}&\:r\le \:\:-0.54545\dots \:\\ \:\:\mathrm{Interval\:Notation:}&\:(-\infty \:\:,\:-\frac{6}{11}]\end{bmatrix}

Please check the attached line graph below.

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Step-by-step explanation:

start by dividing every term by 3

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simplify as much as you can

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combine terms

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x=3, 0

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3 years ago
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