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3 years ago

Which of the following accurately lists all discontinuities of the function below?

Mathematics

2 answers:

jeka943 years ago

5 0

Checking the discontinuity at point -4
from the left f(-4) = 4
from the right f(-4) = (-4+2)² = (-2)² = 4
∴ The function is continues at -4

Checking the discontinuity at point -2
from the left f(-2) = (-2+2)² = 0
from the right f(-2) = -(1/2)*(-2)+1 = 2
∴ The function is jump discontinues at -2

Checking the discontinuity at point 4
from the left f(4) = -(1/2)*4+1 = -1
from the right f(4) = -1
but there no equality in the equation so,
∴ The function is discontinues at 4

The correct choice is the second
point discontinuity at x = 4 and jump discontinuity at x = -2

swat323 years ago

3 0

I hope I can show you my scratch paper. anyway, my answer is
point discontinuity at x=-2

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3 years ago

Use a calculator to find the approximate value of sin-1 (0.549)

tatyana61 [14]

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3 years ago

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Loin has read 25 % of a book. If she has been reading for 5 hours, how many more hours will it take her to complete the book?

Anon25 [30]

Well, the answer is 15 hours

Explanation:
Since it took Loin 5 hours to read 25% of the books and the entire book is 100%, 25% is 1/4 of the book. We add on 5 hours to every 1/4 of the book so 1/2=10 hours, 3/4= 15 hours and the entire book =20 hours. So the entire book would take 20 hours to read but the question is How many MORE hours so we subtract 5 hours from 20 hours which equals 15.

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3 years ago

Can you please answer this question

tamaranim1 [39]

$3tan^{2} \theta +7sec\theta=3$
First I converted the equation terms into sine and cosine.
$tan^{2}\theta = \frac{sin^{2}\theta}{cos^{2}\theta}$ and $sec\theta= \frac{1}{cos\theta}$
Substitution:
$\frac{3sin^2\theta}{cos^2\theta} + \frac{7}{cos\theta} =3$
Common Denominator Created:
$\frac{3sin^2\theta}{cos^2\theta} + \frac{7cos\theta}{cos^2\theta} =3$
Multiply each term by the LCD:
$3sin^2\theta+7cos\theta=3cos^2\theta$
Substitution: Recall ⇒ $sin^2\theta =1-cos^2\theta$
$3(1-cos^2\theta)+7cos\theta=3cos^2\theta$
Distribute and collect all terms on one side:
$6cos^2\theta-7cos\theta-3=0$
Factor and set each factor equal to 0:
$(2cos\theta-3)(3cos\theta+1)=0$
$2cos\theta-3=0$ ⇒ $theta=cos^{-1} \frac{3}{2}$
$3cos\theta+1=0$ ⇒ $theta=cos^{-1} \frac{-1}{3}$
The 2nd factor provides only possible answer 109.5 degrees

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3 years ago

Which of the following is the graph of 2x+3y=6

Bond [772]

Taking point (0,-2) of graph one and replacing in the equation;

2x+3y=6

2(0)+3(-2)=6

-6=6

So graph isn't the required graph.

Taking point (0,2) of graph 2;

2x+3y=6

2(0)+3(2)=6

6=6

So, graph 2 is the required graph.

8 0

3 years ago

Read 2 more answers