The expanded form for that problem would be (7x10^5) + (2 × 10^4) + (8x10^1)
when i put ^then a number i mean to that power like 2 to the 4th power i would write 2^4
Answer:
A. Plane B because it was 9.33 miles away
B. 48 units
Step-by-step explanation:
A. Since the airplanes fly at an angle to the runway, their direction forms a triangle with the runway with their height above the ground as the opposite of the angle and their distance from the airport as the hypotenuse.
So for airplane A with 44° angle of departure,
sin44° = y/h where y = height above the ground and h = distance from airport
So h = y/sin44° = 6/sin44° = 8.64 miles
So for airplane B with 40° angle of departure,
sin40° = y/H where y = height above the ground and H = distance from airport
So H = y/sin40° = 6/sin40° = 9.33 miles
Since airplane B is at 9.33 miles away from the airport whereas airplane A is 8.64 miles from the airport, airplane B is farther away.
B. We know that scale factor = new size/original size
Our scale factor = 4 and original size = 12 units. So,
new size = scale factor original size = 4 × 12 = 48 units.
A graphing calculator is a great help for problems of this nature.
x ∈ {-5.63, -0.55, 2.59}
Answer:
y>2
Step-by-step explanation:
-4-3y>-10
-3y>-10+4
-3y>-6
y>-6/-3
y>2
