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Yakvenalex [24]
2 years ago
9

Write in slope intercept form x intercept -4 ; y intercept 2

Mathematics
1 answer:
Sindrei [870]2 years ago
8 0

Step-by-step explanation:

the slope intercept form is y=mx+b where b is the y intercept which is the starting point of the equation and m is the slope which is x so the answer is y=-4x +2

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Plz help me on number 4 thank u so much math people
Anna [14]
A)5.17
B)10.86
<em>I hope this helps</em>
5 0
2 years ago
The largest angle in a triangle is three times as big as the smallest angle, and the middle angle is twice as big as the smalles
PtichkaEL [24]
Let X = smallest angle
largest 3x
middle=2x. add the 3 angles of any triangle and you get ,180

x+2x+3x=180
6x=180
x= 30
smallest =30
middle=60
largest=90
8 0
2 years ago
Now given a rope hanging from the top of a pole. The end lying on the ground is 3 chi long. When tightly stretchedit is 8 chi fr
drek231 [11]

Answer:

Height of the pole = 9.17 chi.

Length of the rope = 12.17 chi.

Step-by-step explanation:

Given that the rope is hanging from the top of a pole having height x chi and the portion of the rope lying on the ground is 3 chi.

So, the length of the rope= x + 3 chi.

Let AB represents the pole in the figure, and one end of the rope is at point A.

When the rope is tightly stretched, let C be the other end of the rope as shown in the triangle.

The length of the rope = AC.

\Rightarrow AC=x+3 chi.

Distance from the bottom of the pole, point A, to the other end of the pole, point B, is 8 chi.

So, BC=8 chi.

As the triangle ABC is a right-angled triangle, so by using Pythagoras theorem,

AC^2= AB^2+BC^2

\Rightarrow (x+3)^2=x^2+8^2

\Rightarrow x^2+6x+9=x^2+64

\Rightarrow 6x=64-9=55

\Rightarrow x=55/6=9.17 chi.

Hence, the height of the pole, AB=x=9.17 chi,

and the length of the rope, x+3=9.17+3=12.17 chi.

8 0
3 years ago
Evaluate the expression <br> -2.3=
hammer [34]

Answer:-2.3

Step-by-step explanation:

4 0
3 years ago
Thrice a number decreased by 5 exceeds twice the number by a unit find the number
viktelen [127]
Working attached below. Hope this helps! Any questions let me know :)

6 0
2 years ago
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