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zubka84 [21]
3 years ago
5

2(3c + 3) < 6c + 9

Mathematics
1 answer:
Usimov [2.4K]3 years ago
4 0
<h3>Answer: B. All real numbers</h3>

Work Shown:

2(3c+3) < 6c+9

6c+6 < 6c+9 .... distribute

6c+6-6c <6c+9-6c .... subtract 6c from both sides

6 < 9 ... note the c terms go away entirely

We're left with a statement that is always true since 6 is always less than 9 regardless of what value of c we pick. So there are infinitely many solutions. Any real number can replace c to get a true statement.

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Find for x<br><br> 1/5x + 1/3= 3(2/3x -2)
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The value of x  for the given expression is  (95/27)

Step-by-step explanation:

Here, the given expression is:

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Now here  solving for the value of x , we get

\frac{1}{5} x + \frac{1}{3}   = 3(\frac{2}{3}x) -6\\\implies\frac{1}{5} x + \frac{1}{3}   = 2x -6

Now, taking the variable terms on 1 side, we get

\frac{1}{5} x   - 2x   = -6 -  \frac{1}{3} \\\implies\frac{x  - 10x}{5}   = -(\frac{6(3)  +1}{3} )

or, \frac{-9x}{5}   = -\frac{19}{3}   \implies x  = \frac{19}{3}  \times\frac{5}{9}   = \frac{95}{27}

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