2(3c + 3) < 6c + 9

Mathematics

1 answer:

Usimov [2.4K]4 years ago

4 0

<h3>Answer: B. All real numbers</h3>

Work Shown:

2(3c+3) < 6c+9

6c+6 < 6c+9 .... distribute

6c+6-6c <6c+9-6c .... subtract 6c from both sides

6 < 9 ... note the c terms go away entirely

We're left with a statement that is always true since 6 is always less than 9 regardless of what value of c we pick. So there are infinitely many solutions. Any real number can replace c to get a true statement.

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