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3 years ago

Ill give brainliest

Mathematics

1 answer:

Rzqust [24]3 years ago

4 0

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}m+4n=8&(1)\\m=n-2&(2)\end{array}\right\\\\\text{substitute (2) to (1):}\\\\n-2+4n=8\qquad\text{add 2 to both sides}\\5n=10\qquad\text{divide both sides by 5}\\n=2\\\\\text{put the value of}\ n\ \text{to (2):}\\\\m=2-2\\m=0$

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Will mark brainliest for correct answer !!! <3

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4 0

2 years ago

Read 2 more answers

1. Determine a rule that could be used to explain how the volume of a

Eva8 [605]

Answer:

See explanation

Step-by-step explanation:

Solution:-

- We will use the basic formulas for calculating the volumes of two solid bodies.

- The volume of a cylinder ( V_l ) is represented by:

$V_c = \pi *r^2*h$

- Similarly, the volume of cone ( V_c ) is represented by:

$V_c = \frac{1}{3}*\pi *r^2 * h$

Where,

r : The radius of cylinder / radius of circular base of the cone

h : The height of the cylinder / cone

- We will investigate the correlation between the volume of each of the two bodies wit the radius ( r ). We will assume that the height of cylinder/cone as a constant.

- We will represent a proportionality of Volume ( V ) with respect to ( r ):

$V = C*r^2$

Where,

C: The constant of proportionality

- Hence the proportional relation is expressed as:

V∝ r^2

- The volume ( V ) is proportional to the square of the radius. Now we will see the effect of multiplying the radius ( r ) with a positive number ( a ) on the volume of either of the two bodies:

$V = C*(a*r)^2\\\\V = C*a^2*r^2$

- Hence, we see a general rule frm above relation that multiplying the result by square of the multiple ( a^2 ) will give us the equivalent result as multiplying a multiple ( a ) with radius ( r ).

- Hence, the relations for each of the two bodies becomes:

$V = (\frac{1}{3} \pi *r^2*h)*a^2$

$V = ( \pi *r^2*h)*a^2$

8 0

3 years ago

If , n^-3 = 1/8 then n would be which of the following? -1/2 -2 2 1/2

lions [1.4K]

Answer:

Step-by-step explanation:

${n}^{ - 3} = \frac{1}{8} \\ \\ {n}^{ - 3} = \frac{1}{ {2}^{3} } \\ \\ {n}^{ - 3} = {2}^{ - 3}.. (\because \frac{1}{a^n} = a^{-n}) \\ \\ n = 2 \\(\because exponents \: are \: same\: hence\: \\bases\: will \: also\: be\: equal)$