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olya-2409 [2.1K]
3 years ago
12

Can someone please help me solve this

Mathematics
1 answer:
Lady_Fox [76]3 years ago
4 0
The "parent function" is y = (log to the base 2 of) x

The domain of this function is (0, infinity) (all real numbers greater than zero).

The range of this function is the same as above.

If you replace "x" with "x+1" in the parent function, the associated graph will look the same as that of the given function, EXCEPT that it will be translated by 1 unit to the left.

After this has happened, that "-3" will shift the entire new graph downward by 3 units.
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I need help with this
olga55 [171]
3:5 -> 6:10, 9:15, 12:20
8:10-> 4:5,16:20, 24:30
6:8 -> 3:4, 12:16, 30:40
6:18 -> 3:9, 12:36, 30:90
4:8 -> 1:2, 8:16, 12:24
3 0
2 years ago
Find the lowest common multiple of 28 and 210
Grace [21]

Answer:

420

Step-by-step explanation:

210 = 14×15

28 = 14×2

The LCM wil be the product of unique factors;

... LCM = 14×15×2 = 420

3 0
3 years ago
The time, T (seconds) it takes for a pot of water to boil is inversely proportional to the cooker setting, H, applied to the pot
Lera25 [3.4K]

Answer:

T = 96

Step-by-step explanation:

From the question given above, we were told that the time, T (seconds) it takes for a pot of water to boil is inversely proportional to the cooker setting, H. This can be written as:

T ∝ 1/H

T = K/H

Cross multiply

K = TH

Next, we shall determine the value of K. This can be obtained as follow:

H = 8

T = 120

K =?

K = TH

K = 120 × 8

K = 960

Finally, we shall determine the value of T when H = 10. This can be obtained as illustrated below:

H = 10

K = 960

T =.?

T = K/H

T = 960/10

T = 96

6 0
3 years ago
How many times can 66 go into 648
insens350 [35]

Answer:

9

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Please I need help
Dimas [21]

Answer:

Step-by-step explanation:

The directrix is a vertical line, so the parabola is horizontal. The focus lies to the left of the directrix, so the parabola opens to the left.

For a left-opening parabola:

x = a(y-k)²+h,

a < 0,

vertex (h,k)

focal length p = 1/|4a|

focus (h-p, k)

directrix: x=h+p

Apply your data

focus (1,-4)

directrix x=2

vertex (1.5,-4).

focal length p = 0.5

a = -1/|4p| = -½

x = -½(y-2)²+ ½

8 0
2 years ago
Read 2 more answers
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