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3 years ago

Solve for x.

1 answer:

7 0

$-ax+3b \ \textgreater \ 5\ \ \ |subtract\ 3b\ from\ both\ sides\\\\-ax \ \textgreater \ 5-3b\ \ \ \ |change\ signs\\\\ax \ \textless \ 3b-5\ \ \ \ |divide\ both\ sides\ by\ a \ \textgreater \ 0\\\\\boxed{x \ \textless \ \dfrac{3b-5}{a}}\\\\-ax \ \textgreater \ 5-3b\ \ \ \ |divide\ both\ sides\ by\ (-a)\\\\\boxed{x \ \textless \ \dfrac{5-3b}{-a}\to x \ \textless \ \dfrac{-3b+5}{-a} }$

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X +5+11x=12x+Y It says find the value of y that makes each equation true for all values of

sladkih [1.3K]

X + 5 + 11x = 12x + y

Simplify: 12x + 5 = 12x + y (We are adding x and 11x on the left side)

Subtract 12x from each side makes each zero.

5 = y

So we can plug in and test. I'm picking two random numbers to plug in for x. 10, and 82

x = 10, y = 5
10 + 5 + 11(10) = 12(10) + 5
125 = 125

x = 82, y = 5
82 + 5 + 11(82) = 12(82) + 5
989 = 989

So we verified y = 5

3 0

3 years ago

a collector found a bone near former mayan territory. after careful research it has been determined that the bone lost about 15%

Olin [163]

Answer:

পার্সেন্টস সহ এই সূত্রটি মিশ্রিত হয় ...

4 0

2 years ago

PLEASE HELP ME THANK YOU

Sunny_sXe [5.5K]

Answer:

Step-by-step explanation:

That exterior angle of 111 is equal to the sum of the triangle's remote interior angles. We add the 37 + 35 to get a total angle measure of 72. That means that the base angle on the right is 111 - 72 = 39. That 39 degree angle is vertical to x; that means that x = 39 as well.

3 0

3 years ago

Read 2 more answers

Do these numbers 19.657 < 19.67

nexus9112 [7]

I dont understand your question.......

5 0

3 years ago

Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your

Veronika [31]

The expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Given an integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ .

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

$\int\limits^b_a {f(x)} \, dx$ = $\lim_{n \to \infty}$ ∑f(a+iΔx)Δx ,here Δx=(b-a)/n

$\int\limits^5_1 {x/(2+x^{3}) } \, dx$ =f(x)= $x/2+x^{3}$

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)= $[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}$

$\lim_{n \to \infty}$ ∑f(a+iΔx)Δx=

$\lim_{n \to \infty}$ ∑ $n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n$

=4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$

Hence the expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

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5 0

2 years ago