2p² - p - 10 = 0
2 = a
- 1 = b
- 10 = c
To factor, find two numbers that multiply to equal a·c and also that have a sum of b
2p² + 4p - 5p - 10 = 0
2p (p + 2) - 5 (p + 2) = 0
<h3>Answer: ( 2p - 5 ) ( p + 2 ) = 0</h3>
Answer:
(-1,-6)
Step-by-step explanation:
Plug 6x for y into the bottom equation:
2x+3(6x)= -20
2x+18x= -20
20= -20
x= -1
Substitute -1 for x in the equation for y:
y=6(-1)
y=-6
I hope I could help :)
Answer:
3x >/= 24 or 3x </= -24
Step-by-step explanation:
Plug in (-8) for (x) and solve.
The rule for this rotation is (x, y) converted into (-y, x). So, to find the answer you would make the y negative and switch the values in the ordered pair. A would be (3, -2), B would be (3, -5), and C would be (2, -4). So, your answer would be B. Hope this helps!
I don’t know the answer but I need points sorry
