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blondinia [14]
3 years ago
5

Solve the algebraic equation: 2x + 4 = -16​

Mathematics
2 answers:
lora16 [44]3 years ago
5 0

Answer:

-10

Step-by-step explanation:

subtract 4 from both sides

divide by 2

zalisa [80]3 years ago
3 0

Answer:x= -10

Step-by-step explanation

first add 4 to both sides of the equation which will cancel out the 4 and leave you with 2x= -20

then divide both sides by 2 to get the x by itself and divide -20 by 2 which will give you x= -10

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In this question, the domain of discourse is a set of employees who work at a certain company. Ingrid is one of the employees at
krek1111 [17]

Answer:

Step-by-step explanation:

Define Sets:

S(x): x was sick yesterday

W(x): x went to work yesterday

V(x): x was on vacation yesterday

Find:

Logical expression with the same meaning of:

(a) Everyone was well and went to work yesterday.

(b) Everyone who was sick yesterday did not go to work.

(c) Yesterday someone was sick and went to work.

(d) Someone who missed work was neither sick nor on vacation

(e) Ingrid was sick yesterday but she went to work anyway.

Solution:

a) Everyone was well and went to work. People who could have possibly gone to work would have been who were well or un-well so the the resulting set would be.

                             A (x) = W(x) - (W(x) & S(x))

b) Everyone who was sick and did not go to work. Sick people may or may not go to work. Hence, the domain can be defined as:

                             B (x) = S(x) - (W(x) & S(x))

c) Someone who was sick and did not go to work. Sick people may or may not go to work. Hence, the domain can be defined as:

                             C (x) ⊆ (W(x) & S(x))

d) Someone who missed work was not sick not on vacation:

                             D (x) = ( W'(x) & S'(x) & V'(x))

e) Ingrid was sick but went to work,, answer to part c and e are the same

                             E (x) = C(x) ⊆ (W(x) & S(x))  

5 0
3 years ago
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enyata [817]

<span>a.\\8m+5\geq5\&#10;\ \ |-5\\8m\geq0\ \ \ |:8\\m\geq0\to m\in\left

b.\\6m\leq-36\ \ \ |:6\\m\leq-6\to m\in\left(-\infty;\&#10;-6\right>\\\\m+24 > 20\ \ \ |-24\\m > -4\to m\in(-4;\&#10;\infty)\\\\solution:\ m\in\left(-\infty;\ -6\right>\ \cap\ (-4;\ \infty)\to&#10;m\in\O\to NO\ SOLUTION

c.\\-2m < 6\ \ \ |:(-2)\\m > -3\to m\in(-3;\ \infty)\\\\3m > 24\&#10;\ \ |:3\\m > 8\to m\in(8;\ \infty)\\\\solution:\ m\in(-3;\ \infty)\ \cap\&#10;(8;\ \infty)\to m\in(8;\ \infty)

d.\\m+9 < 8\ \ \ |-9\\m < -1\to m\in(-\infty;\ -1)\\\\-2m \geq10\ \&#10;\ |:(-2)\\m\leq-5\to m\in\left(-\infty;-5\right>\\\\solution:\&#10;m\in(-\infty;\ -1)\ \cap\ \left(-\infty;-5\right>\to&#10;m\in\left(-\infty;-5\right></span>


6 0
4 years ago
PLEASE HELP ME WITH THIS!!!!
Mashcka [7]

Answer:

6.5/x=10/40;x=26

Step-by-step explanatio

8 0
3 years ago
Read 2 more answers
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stiv31 [10]

Answer:

Step-by-step explanation:

Distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\\\\ =\sqrt{(-8-7)^{2}+(4-4)^{2}}\\\\ =\sqrt{(-15)^{2}+0}\\\\=\sqrt{225} \\\\=15

5 0
4 years ago
Which equation will solve the following word problem? One small pitcher and one large pitcher can hold 12 cups of water. If the
Delicious77 [7]
Option 3
Amount of water hold by both the pitchers (Large + small) = 12 cups
Let the small pitcher holds the water = S cups
If the water hold by the large pitcher is twice the size of the small pitcher, then the amount of water hold by large pitcher = 2S
Total amount water hold by both = S + 2S
Equation for this situation will be,
S + 2S = 12
Therefore, Option (3) will be the answer.
6 0
3 years ago
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