The statement best describes Cheryl's computer is option C. Cheryl accelerated to 65 mph, drove at a constant speed for 5.5 minutes, and then decelerated to 45 mph.
<h3>How to find the function which was used to make graph?</h3>
A graph contains data of which input maps to which output.
Analysis of this leads to the relations which were used to make it.
If we know that the function crosses the x-axis at some point, then for some polynomial functions, we have those as roots of the polynomial.
Let's assume the graph of Cheryl's commute was like the one below.
We can see that she started at 0 mph.
One minute later, she was up to 65 mph, so she had accelerated (increased her speed).
At 6.5 min (5.5 min later) her speed was still 65 mph therefore, she was driving at a constant speed.
Over the next 2.5 min, her speed dropped to 45 mph, therefore she was decelerating.
Learn more about finding the graphed function here:
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Approximately equal to symbol
And it’s mostly used in terms of numerical approximations
Answer:
The length of the longer ladder is 35 ft
Step-by-step explanation:
Please check the attachment for a diagrammatic representation of the problem
We want to calculate the length of the longer ladder ;
We make reference to the diagram
Since the two right triangles formed are similar. the ratios of their sides are equal;
Thus;
20/15 = 28/x + 15
20(x + 15) = 15(28)
20x + 300 = 420
20x = 420-300
20x = 120
x = 120/20
x = 6
So we want to calculate the hypotenuse of a right triangle with other sides 28ft and 21 ft
To do this, we use the Pythagoras’ theorem which states that square of the hypotenuse equals the sum of the squares of the two other sides
Let the hypotenuse be marked x
x^2 = 28^2 + 21^2
x^2 = 1,225
x = √1225
x = 35 ft
OK so first I like to find what 10% is which in this case would be 1.8 and to find the other 5% you divide 1.8 by 2 which gets you .9 if you and 1.8 and .9 you get 2.7 and if you add 2.7 to 18 you get 20.7 which is your retail price
We have to rewrite the expression so that it has no denominator.
For example:
1 / x = x^(-1)
1/8 = 8^(-1); 1/x^(4) = x^(-4); 1/y^(3) = y^(-3); 1/z = z^(-1).