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elena55 [62]
3 years ago
12

In Volleyball , players serve the ball to the opposing team . If the opposing team fails to hit the ball , the services is calle

d an ace . A player's ace average is the number of aces served divided by the number of games played . A certain player has an ace average of 0.3 and has played in 70 games this season .
How many aces has the player served ?
Mathematics
1 answer:
choli [55]3 years ago
6 0
To solve, I would write an equation like this: 0.3=x/70 , where x is the number of aces divided by 70 games and 0.3 is his ace average.

0.3=x/70
x=70x0.3
  =21

The player has served 21 aces.

Check:
21/70
=0.3


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We have been given that a person places $6340 in an investment account earning an annual rate of 8.4%, compounded continuously. We are asked to find amount of money in the account after 2 years.

We will use continuous compounding formula to solve our given problem as:

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2 years ago
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2.10 Guessing on an exam: In a multiple choice exam, there are 6 questions and 4 choices for each question (a, b, c, d). Nancy h
ololo11 [35]

Answer:

a) p = (3/4)^5 *(1/4) =0.0593

b) P(X=6) = (6C6) (0.25)^6 (1-0.25)^{6-6}= 0.000244

c) P(X \geq 1)

And we can use the complement rule like this:

P(X \geq 1) = 1-P(X

P(X=0) = (6C0) (0.25)^0 (1-0.25)^{6-0}= 0.17798

And replacing we have:

P(X \geq 1) = 1-P(X

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

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We can model the number of correct questions answered with a binomial distribution X \sim Binom(n = 6, p = 1/4=0.25)

Solution to the problem

Assuming the following questions:

a) the first question she gets right is the 6th question?  

For this case we want the first 5 questions incorrect and the last one correct, assuming independence we have:

p = (3/4)^5 *(1/4) =0.0593

(b) she gets all of the questions right?

For this case we want all the questions right so then we want this:

P(X=6) = (6C6) (0.25)^6 (1-0.25)^{6-6}= 0.000244

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For this case we want this probability:

P(X \geq 1)

And we can use the complement rule like this:

P(X \geq 1) = 1-P(X

P(X=0) = (6C0) (0.25)^0 (1-0.25)^{6-0}= 0.17798

And replacing we have:

P(X \geq 1) = 1-P(X

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Answer:

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