What's the answer to this?

-3+(-6) is ___ units from -3 in the positive or negative direction.

Lisa [10]

Answer:

-3+(-6) = -9

Step-by-step explanation:

a negative 3 plus another negative 6 is a negative 9. Is just like if you borrow $3 from your friend and borrow $9 from another friend. That means you own two of your friends a total of $9. This can be mathematically illustrate as: -3 + (-6)= -9

3 0

3 years ago

A circle with an area 9pi has a sector with a central angle of 1/9pi what is the area of the sector

ludmilkaskok [199]

Answer:

½pi or 0.5pi units²

Step-by-step explanation:

Area : angle

9pi : 2pi

x : pi/9

9pi/2pi = x/(pi/9)

4.5 × pi/9 = x

x = ½pi or 0.5pi units²

8 0

3 years ago

Which part of a fraction tells how many parts it takes to make a whole? (Numerator of denominator?)

solmaris [256]

The denominator will tell how many parts it takes to make a whole

4 0

3 years ago

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Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

$f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0 } \atop {0}; Otherwise} \right.$

The value of constant C can be obtained as:

$\int_x( {\int_y( {\int_z {f(x,y,z)} \, dz }) \, dy }) \, dx = 1$

$\int\limits^\infty_0 ({\int\limits^\infty_0 ({\int\limits^\infty_0 {Ce^{-(0.5x + 0.2y + 0.1z)} } \, dz }) \, dy } )\, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y }(\int\limits^\infty_0 {e^{-0.1z} } \, dz }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ]) } \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}] } \, dy }) \, dx =1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0 }) \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}] } \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}] } \, dx = 1$

$50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1$

$50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1$

$50C[0+\frac{1}{0.5} ] =1$

$100C = 1$ ⇒ $C = \frac{1}{100}$

C = 0.01

3 0

3 years ago

50 POINTS!! PLEASE ASAP. The director of a local ballet company needs to print the programs for the next performance. Janet’s Pr

Maru [420]

For this case we find the expression that represents the cost of each printing press.

x: Be the variable that represents the number of programs to print

So:

Cost 1: Janet’s Print Shop

$C (x) = 0.25x + 35$

Cost 2: The Printing Press

$C (x) = 0.15x + 50$

If we want to find the number of programs for which the costs are the same, then we equate both equations:

$0.25x + 35 = 0.15x + 50\\0.25x-0.15x = 50-35\\0.1x = 15\\x = \frac {15} {0.1}\\x = 150$

Thus, for 150 programs the cost is the same.

Answer:

For 150 programs the cost is the same.

5 0

3 years ago

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