Answer:
It's when rates are expressed as quantities.
Step-by-step explanation:
An example would be miles per hour (mph). People use these to determine the distance they will go in an amount of time and to judge safe speed.
<em><u>Before you read this!!</u></em><em> To me, it looks like 8 is the entire length of lineJL, but it may only be the length of lineJM. I've written the steps for lineJL=8 NOT lineJM=8. If this is not the case and 8 is only the length of lineJM let me know so I can fix my answer!</em>
Step-by-step explanation:
The area of a triangle is A=1/2(b)(h)
B=base
H=height
Your height is found in the line in the middle of the triangle, for you it is 6.
The base is the long bottom line on the triangle (lineJL), for you it is 8.
So let's put it in.
A=1/2(8)(6)
A=24sq units (C)
Answer:
Step-by-step explanation:
(x+4)² + y² = 1.5²
Answer:
3/5
Step-by-step explanation:
We need to use the trig identity that cos(2A) = cos²A - sin²A, where A is an angle. In this case, A is ∠ABC. Essentially, we want to find cos∠ABC and sin∠ABC to solve this problem.
Cosine is adjacent ÷ hypotenuse. Here, the adjacent side of ∠ABC is side BC, which is 4 units. The hypotenuse is 2√5. So, cos∠ABC = 4/2√5 = 2/√5.
Sine is opposite ÷ hypotenuse. Here, the opposite side of ∠ABC is side AC, which is 2 units. The hypotenuse is still 2√5. So sin∠ABC = 2/2√5 = 1/√5.
Now, cos²∠ABC = (cos∠ABC)² = (2/√5)² = 4/5.
sin²∠ABC = (sin∠ABC)² = (1/√5)² = 1/5
Then cos(2∠ABC) = 4/5 - 1/5 = 3/5.
<span>Answer:
rc length=â«âšr2+(drdθ)2â‹…dθ
for a equation r=θ2,
drdθ=2θ
â´ Arc length=â«âšÎ¸4+4θ2â‹…dθ
by factoring out θ and rewriting a bit,
=â«Î¸âšÎ¸2+4â‹…dθ=12â«(θ2+4)12â‹…2θdθ
by General Power Rule,
=12⋅(θ2+4)3232+k=13(θ2+4)32+k
Let's assume that 0≤θ≤2π
Arc length=â«2Ď€0âšÎ¸4+4θ2â‹…dθ=92.9</span>
