Answer:
Step-by-step explanation:
When 3 is divided by 2, the quotient is 1 and remainder is 1
Whole number is the quotient.
Fraction : <u>remainder</u>
divisor
![1\frac{1}{2}](https://tex.z-dn.net/?f=1%5Cfrac%7B1%7D%7B2%7D)
Let the side of the square plate be x cm.
The height of the box is 3 cm.
The length & width are both (x-6) cm.
volume = length*width*height
=3*(x-6)*(x-6)
=80
x can then be obtained by solving
3(x-6)(x-6)=80
Answer:
What am I supposed to solve??
Step-by-step explanation:
I'll give you the actual answer in the comments afterwards.
Answer:
Center: (2,-1)
Radius: 4 units
Step-by-step explanation:
Equation of the circle in standard form is:
![x^{2}+y^{2}+2gx+2fy+c=0](https://tex.z-dn.net/?f=x%5E%7B2%7D%2By%5E%7B2%7D%2B2gx%2B2fy%2Bc%3D0)
The radius of this circle is located at (-g, -f) and its radius is equal to:
![r=\sqrt{g^{2}+f^{2}-c}](https://tex.z-dn.net/?f=r%3D%5Csqrt%7Bg%5E%7B2%7D%2Bf%5E%7B2%7D-c%7D)
The given equation of circle is:
![x^{2}+y^{2}-4x+2y-11=0](https://tex.z-dn.net/?f=x%5E%7B2%7D%2By%5E%7B2%7D-4x%2B2y-11%3D0)
Re-writing this equation in a form similar to the standard equation:
![x^{2}+y^{2}+2(-2)x+2(1)y-11=0](https://tex.z-dn.net/?f=x%5E%7B2%7D%2By%5E%7B2%7D%2B2%28-2%29x%2B2%281%29y-11%3D0)
Comparing this equation with standard equation we can say:
g= -2
f = 1
c = -11
So, the center of the circle will be located at (-g, -f) = (2, -1)
And the radius will be = ![\sqrt{g^{2}+f^{2}-c} =\sqrt{(-2)^{2}+(1)^{2}-(-11)} =\sqrt{16} =4](https://tex.z-dn.net/?f=%5Csqrt%7Bg%5E%7B2%7D%2Bf%5E%7B2%7D-c%7D%20%3D%5Csqrt%7B%28-2%29%5E%7B2%7D%2B%281%29%5E%7B2%7D-%28-11%29%7D%20%3D%5Csqrt%7B16%7D%20%3D4)
Thus the radius of the given circle is 4 units.
Well therare 318 fiction books and it says the number of non-fiction books is 47 less so what is 318-47.