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4 years ago

12

There are 6 red marbles, 8 blue marbles, and 11 green marbles in a bag. What is the probability that you will randomly draw eith

er a red or a blue marble?
24%
56%
32%
10%

2 answers:

belka [17]4 years ago

8 0

56%
its the correct answer i know it is

o-na [289]4 years ago

5 0

<span>6/25 + 8/25 =0.56
</span><span>0.56 or as a percent 56%SO the answer is B 56%
</span>

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The price of a house is originally listed at $155,000. The owners are having a hard time selling it and decide to reduce the pri

saul85 [17]

Answer:

83%

Step-by-step explanation:

We can put this into a fraction to get the ratio of the new price over the old price

$\frac{128650}{155000}$

This will give us the percentage of how much was decreased.

The answer you get is .83

Bring 2 decimal places to the right to get 83 (converting from decimal to percentage)

You get 83 percent to be your answer

3 0

2 years ago

Read 2 more answers

What percent of 20 is 16?!!!<br><br>What's the answer and how do I work the problem out?!!

-Dominant- [34]

<span>16/20 is 80%.</span>

You find out by multiplying the denominator: 20 * 5 = 100

Then, you do the same to the numerator which is: 16 * 5 = x

So, x = 80%

Hope this helps! :D

7 0

4 years ago

What is the equation for the points (-3,1) and (9,7)

Scorpion4ik [409]

Answer:

The equation of line with given points is 2Y - X - 5 = 0

Step-by-step explanation:

Given points are ( - 3 , 1) and (9 , 7)

Equation of line is y = mx +c

where m is the slop of line

Now m = $\frac{y2 - y1}{x2 - x1}$

Or, m = $\frac{7 - 1}{9 + 3}$

so, slop = $\frac{6}{12}$

∴ slop = $\frac{1}{2}$

Now the equation of line with points ( -3 , 1) and slop m is :

Y - y1 = m ( X - x1)

Or, Y - 1 = $\frac{1}{2}$ (X + 3)

Or, 2Y - X - 5 = 0

Hence The equation of line with given points is 2Y - X - 5 = 0 Answer

6 0

3 years ago

Please help quick it’s a test

disa [49]

The rate must be in DECIMAL form and the time must be in YEARS

8 0

3 years ago

Estimate the quotients using compatibale numbers. 8631÷10

FrozenT [24]

Well what you would have to do is look for numbers that are easy to divide. For example, lets try 9000/10, and so the answer would be 900 and so if you divide the actually numbers, you could compare them, and see if 900 would be a reasonable.

7 0

4 years ago