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REY [17]
2 years ago
9

A set of counters is numbered 1 through 12. Suppose you draw one counter without looking. What is the probability of choosing a

number greater than 4?
Question 5 options:

2/3


1/12


1/3


1/6
Mathematics
1 answer:
crimeas [40]2 years ago
4 0
8 numbers are greater than 4
8/12 = 2/3
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Please answer with steps thank you :)
mart [117]
200×180 =36,000
36,000 / pi (approx 3.14)= 11,459.1559026
4 0
3 years ago
Emily is 68 years old. Colin is 17 years older than Emily. Dan is 16 years younger than Emily. What is the total of their combin
Oksanka [162]

Answer:

205 years

Step-by-step explanation:

E=68 years

C=E+17=68+17=85 years

D=E-16=68-16=52 years

Total=E+C+D=68+85+52=205 years

7 0
3 years ago
181 is 22% of what number?
baherus [9]

Answer:

Step-by-step explanation:822.73

6 0
3 years ago
Read 2 more answers
Determine the measure of each segment then indicate whether the statements are true or false
kupik [55]

Answer:

d_{AB}\ne d_{JK}

d_{AB}\ne \:d_{GH}

d_{GH}\ne \:d_{JK}

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

  • A(-4, 4)
  • B(2, 5)

Finding the length of AB using the formula

d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

        =\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}

         =\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}

         =\sqrt{6^2+1}

         =\sqrt{36+1}

        =\sqrt{37}

d_{AB}\:=\sqrt{37}

d_{AB}=6.08 units        

Given the vertices of the segment JK

  • J(2, 2)
  • K(7, 2)

From the graph, it is clear that the length of JK = 5 units

so

d_{JK}=5 units

Given the vertices of the segment GH

  • G(-5, -2)
  • H(-2, -2)

Finding the length of GH using the formula

d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

         =\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}

          =\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}

          =\sqrt{3^2+0}

           =\sqrt{3^2}

\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0

d_{GH}\:=\:3 units

Thus, from the calculations, it is clear that:

d_{AB}=6.08  

d_{JK}=5

d_{GH}\:=\:3

Thus,

d_{AB}\ne d_{JK}

d_{AB}\ne \:d_{GH}

d_{GH}\ne \:d_{JK}

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

8 0
3 years ago
HURRY will mark brainliest <br>which one of the following graphs is not a function?? :)​
bonufazy [111]

Answer:

I think its A i'm sorry if its wrong

Step-by-step explanation:

5 0
3 years ago
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