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NemiM [27]
3 years ago
14

Find the perimeter and area of each quadrilateral.​

Mathematics
1 answer:
andrezito [222]3 years ago
7 0
The red one is A-49 P-28. Orange is A-96 P-40
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If x varies directly with y and x = 3.5 when y = 14, find x when y = 18.
maks197457 [2]

Answer:

x = 4.5

Step-by-step explanation:

there's definitely other ways to solve this, but I used a proportion.

\frac{3.5}{x} = \frac{14}{18}

Then you can make this equation:

14x = 3.5 * 18

I solved for it and got 4.5 .

5 0
3 years ago
What is the area of parallelogram ABCD
larisa86 [58]

Answer:

20 square units

Step-by-step explanation:

You count how many across the parallelogram is (which is 4) and you count how high it is (which is 5). Then you multiply 5×4* which equals 20 square units.

*The reason you do this is because base×hieght=area

7 0
3 years ago
Read 2 more answers
HELP, HELP PLEASE I NEED HELP!
bogdanovich [222]

Answer:

120 inches

Step-by-step explanation:

8 times 15 is 120

7 0
2 years ago
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The diameter of a tire is 2.5 ft. Use this measurement to answer parts a and b. Show all work to receive full credit
Alla [95]

Answer:

The answer is below

Step-by-step explanation:

The diameter of a tire is 2.5 ft. a. Find the circumference of the tire. b. About how many times will the tire have to rotate to travel 1 mile?

Solution:

a) The circumference of a circle is the perimeter of the circle. The circumference of the circle is the distance around a circle, that is the arc length of the circle. The circumference of a circle is given by:

Circumference = 2π × radius; but diameter = 2 × radius. Hence:

Circumference = π * diameter.

Given that diameter of the tire = 2.5 ft:

Circumference of the tire = π * diameter = 2.5 * π = 7.85 ft

b) since the circumference of the tire is 7.85 ft, it means that 1 revolution of the tire covers a distance of 7.85 ft.

1 mile = 5280 ft

The number of rotation required to cover 1 mile (5280 ft) is:

number of rotation = \frac{5280\ ft}{7.85\ ft\ per\ rotation}=672\ rotations\\\\\\

4 0
3 years ago
Read 2 more answers
Show that y=cos(t)y=cos(t) is a solution to (dydt)2=1−y2(dydt)2=1−y2. Enter your answers below in terms of the independent varia
GrogVix [38]

Answer:

(\frac{dy}{dt})^2=sin^2t

Step-by-step explanation:

y=cost

DE :(\frac{dy}{dt})^2=1-y^2

If y is a solution of given DE then it satisfied the DE.

Differentiate w.r.t t

\frac{dy}{dt}=-sint

Using the formula

\frac{d(cosx)}{dx}=-sinx

LHS:(\frac{dy}{dt})^2=(-sint)^2=sin^2t

RHS

1-y^2=1-cos^2t=sin^2t

By using the formula

sin^2t=1-cos^2t

LHS=RHs

Hence, y is a solution of given DE

(\frac{dy}{dt})^2=sin^2t

7 0
3 years ago
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