Try measuring a different way, maybe with just cups
Answer:
Step-by-step explanation:
we know that distance d from the focus to P should be the same to the distance from P to the directrix
(x-h)^2=4p(y-k)
we need to find the y coordinate,
x is the same from focus, 3
y=(3, (4+2)/2)=(3,3)
we find p now by subtracting the y from the focus from the y that we just found
p=4-3=1
again (x-h)^2=4p(y-k), p=1
(x-3)^2=4(1)(y-3)
(x-3)^2=4(y-3), (x-3)^2=4y-12
simplify
4y=(x-3)^2+12
y=((x-3)^2)/4 + 3
Step-by-step explanation:
Attack on titán
Levi!!!!
The answer to that would be many
Answer:
-sinx
Step-by-step explanation:
a trig identity that is crucial to solving this problem is: sin^2 + cos^2 = 1
with knowing that, you can manipulate that and turn it into 1 - sin^2x = cos^x
so 1-sin^2x/sinx - cscx becomes cos^2x/sinx - cscx
it is also important to know that cscx is the same thing as 1/sinx
knowing this information, cscx can be replaced with 1/sinx
(cos^2x)/(sinx - 1/sinx)
now sinx and 1/sinx do not have the same denominator, so we need to multiply top and bottom of sinx by sinx; it becomes....
cos^2x
---------------------
(sin^2x - 1)/sinx
notice how in the denominator it has sin^2x-1 which is equal to -cos^2x
so now it becomes:
cos^2x
--------------
-cos^2x/sinx
because we have a fraction over a fraction, we need to flip it
cos^2x sinx
---------- * ----------------
1 - cos^2x
because the cos^2x can cancel out, it becomes 1
now the answer is -sinx
